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emmasim [6.3K]
3 years ago
6

Myriah wants to use dimensional analysis to find out how many centimeters (cm) are in 1.4 meters (m).

Chemistry
1 answer:
WINSTONCH [101]3 years ago
4 0
1400 centimeters in 1.4 millimeters
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What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr]
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The answer is C) Xe 4f14 5d10 6s2 6p3

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Two people, one with a blood type and one with ab blood type have four children. What blood types should the children be?
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What mass of iron(II) oxide must be used in the reaction given by the equation below to release 44.7 kJ? 6FeO(s) + O2(g) => 2
zavuch27 [327]

<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37

<u>Explanation:</u>

The given chemical reaction follows:

6FeO(s)+O_2(g)\rightarrow 2Fe_3O_4(s);\Delta H^o=-635kJ

By Stoichiometry of the reaction:

When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.

So, when 44.7 kJ of energy is released, \frac{6}{635}\times 44.7=0.423mol of iron (II) oxide is reacted.

Now, calculating the mass of iron (II) oxide by using the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of iron (II) oxide = 0.423 moles

Molar mass of iron (II) oxide = 71.8 g/mol

Putting values in above equation, we get:

0.423mol=\frac{\text{Mass of FeO}}{71.8g/mol}\\\\\text{Mass of FeO}=(0.423mol\times 71.8g/mol)=30.37g

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37

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For example you have Carbon 12  with 6 protons and 6 neutrons and Carbon 14 with 6 protons and 8 neutrons.

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Take the molar mass of lithium from your periodic table and multiply it by 3.5 moles
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