Children will be 1/4 type A, 1/2 type AB, or 1/4 type B
<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37
<u>Explanation:</u>
The given chemical reaction follows:

By Stoichiometry of the reaction:
When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.
So, when 44.7 kJ of energy is released,
of iron (II) oxide is reacted.
Now, calculating the mass of iron (II) oxide by using the equation:

Moles of iron (II) oxide = 0.423 moles
Molar mass of iron (II) oxide = 71.8 g/mol
Putting values in above equation, we get:

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37
Answer:
A. Isotope
Explanation:
For example you have Carbon 12 with 6 protons and 6 neutrons and Carbon 14 with 6 protons and 8 neutrons.
Take the molar mass of lithium from your periodic table and multiply it by 3.5 moles