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Natali5045456 [20]
3 years ago
14

Mitosis and Meiosis is dividing which organelle?

Chemistry
1 answer:
irinina [24]3 years ago
5 0

Answer:

D

Explanation:

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The table below gives the atomic mass and relative abundance values for the three isotopes of element M.
Serhud [2]

The average atomic mass formula is:

average atomic mass = \Sigma (percent abundane)\times (atomic mass)

Substituting the values in the formula:

average atomic mass = \frac{78.99\times 23.9850+10\times 24.9858+11.01\times 25.9826}{100}

average atomic mass = \frac{1894.57515+249.858+286.068426}{100}

average atomic mass = 24.30516 amu

Hence, 24.30516 amu is the average atomic mass of element M.

7 0
3 years ago
HELP! <br><br>How many moles of a solute would 3 liters of a 2-molar solution contain? ​
katrin [286]

Answer: If it was 3 mol of solute in 2 L of solution it would be 1.5 mol/L.

However when the solute dissolves in the water creating the solution, the volume increases. So 3 mol of solute in 2 L of water creates more than 2 L of solution.

The correct method for making a 3 mol/L solution would be to place some water into a two liter volume container. Dissolve all 3 mol of the solute into the water. Then add water to the 2 L mark. Now there is 3 mol of solute and 2 L of solution.

Explanation: I hope this helps XDDDD

8 0
2 years ago
In the ground-state electron configuration of fe3+, how many unpaired electrons are present? express your answer numerically as
Virty [35]
Answer:
            Iron has 5 unpaired electrons in Fe⁺³ state.

Explanation:

Iron having atomic number 26 has following electronic configuration in neutral state.

                             Fe =  1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁶

When Iron looses three electrons it attains +3 charge with following electronic configuration.

                             Fe⁺³ =  1s², 2s², 2p⁶, 3s², 3p⁶, 3d⁵

The five electrons in d-orbital exist in unpaired form as,

                          3(dz)¹, 3d(xz)¹, 3d(yz)¹, 3d(xy)¹, 3(dx²-y²)¹


3 0
3 years ago
A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
Ulleksa [173]

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




7 0
3 years ago
Which of the following is the ultimate byproduct of weathering?
NikAS [45]
Soil
the answer is soil

6 0
3 years ago
Read 2 more answers
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