The question is asking for the lower bound of the 95% two tailed Confidence interval of the normally distributed population.
95% C.I. is given by 200 + or - 1.96(25) = 200 + or - 49 = (151, 249)
Therefore, the minimum weight of the middle 95% of players is 151 pounds.
Answer:
rocky???
Step-by-step explanation:
5/2 3/8
Answer: 127,500
Step-by-step explanation: I just used a calculator
Hmmm, I think it’s 17. Three quarters of 128 is 96. 96 minus 37 is 59. And then 1/3 of 96 is 32, so 59 minus 32 is 17. Then there remains 17 students! So 17 students have horses. I hope this helped!
