Answer:
1/8
Step-by-step explanation:
sin²(π/8) − cos⁴(3π/8)
Use power reduction formulas:
1/2 (1 − cos(2×π/8)) − 1/8 (3 + 4 cos(2×3π/8) + cos(4×3π/8))
Simplify:
1/2 (1 − cos(π/4)) − 1/8 (3 + 4 cos(3π/4) + cos(3π/2))
1/2 (1 − √2/2) − 1/8 (3 + 4 (-√2/2) + 0)
1/2 − √2/4 − 1/8 (3 − 2√2)
1/2 − √2/4 − 3/8 +√2/4
1/2 − 3/8
1/8
<span>9540000 = 9x1000000 + 5x100000 + 4x10000
= 9x10^6 + 5x10^5 + 4x10^4</span>
Step-by-step explanation:
Answer:
2.86 quarts ( approx )
Step-by-step explanation:
Given,
The initial quantity of the Mr. Gittleboro's radiator that contains 30% antifreeze = 10 quarts,
Let x quarts of pure antifreeze replaced x quarts of Mr. Gittleboro's radiator to bring it up to a required 50% antifreeze,
So, the quantity of 30% antifreeze radiator after drained off x quarts = (10-x) quarts
Also, the quantity of final antifreeze radiator 50% antifreeze = 10 quarts
Thus, we can write,
30% of (10-x) + 100% of x = 50% of 10
30(10-x) + 100x = 500
300 - 30x + 100x = 500
300 + 70x = 500
70x = 200
x = 2.85714285714 quarts ≈ 2.86 quarts
