Ithink that the answer is C)
Answer:
A. Arbitrary code execution
Explanation:
A buffer-overrun, also known as buffer overflow occurs when a programmer makes an error during coding, which could make his system easily susceptible to attacks from a hacker. The root cause of this problem is an overflow of data in a buffer, and programs that are written in C and C+ + are more likely to be affected by this problem. When a buffer-overrun occurs, it would most likely lead to arbitrary code execution.
Arbitrary code execution is an uncontrolled and unrestricted coding by the attacker which alters the original coding. The attacker could input more information into the coding, which alters the original information and which would make the application porous and accessible by just anyone. It is important that programmers run regular tests on their programs, so as to detect any coding errors.
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
Answer:
c-Either A or B
Explanation:
The non-inverting amplifier usually has the input voltage connected to the non-inverting input while the inverting input is connected to the output.
Both the unit gain amplifier and the voltage follower have an input voltage connected to the non-inverting input, and the inverting input connected to the output, so both are special cases of the non-inverting amplifier.
The correct answer is
c-Either A or B
