Which point on the number line below represents a number that is less than -2.5 but greater than -7.5?

Someone pls help me and i will make you a brainlist if i get it right

WITCHER [35]

Answer:

I think the correct answer is D

Step-by-step explanation:

5 0

2 years ago

A square is always a rectangle but a rectangle is not always a square. Which of the following characteristics are shared by a sq

german

A.) Bisecting Diagonals
B.) Four right angles
D.) Two pair of opposite parallel sides
E.) Two pair of opposite congruent sides

Hope this helps!

7 0

3 years ago

Read 2 more answers

Find the Surface Area of the cone.

Snezhnost [94]

Answer:

$\sf \huge{\boxed{\sf area = 653.1 cm^2}}$

Explanation:

$\sf \boxed{\sf area \ of \ cone=\pi r^2 +\pi rl }$

Given:

radius: 8 m

slant height: 18 m

using this formula:

$\hookrightarrow \sf \pi r^2 + \pi rl$

$\hookrightarrow \sf (3.14)(8)^2 +(3.14)(8)(18)$

$\hookrightarrow \sf 653.1 cm^2$

7 0

2 years ago

Sasha has 3.20 in U.S. coins. She has the same number of quarters and nickels. What is the greatest number of quarters she could

RSB [31]

Answer:

10 quarters = $2.50

10 nickels = $0.50

that leaves $0.20 for other coins (dimes / pennies)

Step-by-step explanation:

First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.

Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.

This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.

8 0

3 years ago

Read 2 more answers

If I chose a number uniformly from the integers from 1 to 25, calculate the conditional probability that the number is a multipl

topjm [15]

Answer:

Step-by-step explanation:

If I choose a number from the integers 1 to 25, the total number of integers I can pick is the total outcome which is 25. n(U) = 25

Let the probability that the number chosen at random is a multiple of 6 be P(A) and the probability that the number chosen at random is is larger than 18 be P(B)

P(A) = P(multiple of 6)

P(B) = P(number larger than 18)

A = {6, 12, 18, 24}

B = {19, 20, 21, 22, 23, 24, 25}

The conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is expressed as P(A|B).

P(A|B) = P(A∩B)/P(B)

Since probability = expected outcome/total outcome

A∩B = {24}

n(A∩B) = 1

P(A∩B) = n(A∩B)/n(U)

P(A∩B) = 1/25

Given B = {19, 20, 21, 22, 23, 24, 25}.

n(B) = 7

p(B) = n(B)/n(U)

p(B) = 7/25

Since P(A|B) = P(A∩B)/P(B)

P(A|B) = (1/25)/(7/24)

P(A|B) = 1/25*25/7

P(A|B) = 1/7

Hence the conditional probability that the number is a multiple of 6 (including 6) given that it is larger than 18 is 1/7

7 0

3 years ago