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3 years ago

Solve the following 1) 2(x + 3) = x - 42) 4(5x-2) = 2(9x+3)PLS HELP

Mathematics

1 answer:

gayaneshka [121]3 years ago

6 0

Answer:

(1) $x = -4$ (2) $x = 7$

Step-by-step explanation:

From the first equation:

$2(x + 3) = x - 4\\\implies x = 2(x + 3) + 4\\\implies x = 2x + 6 + 4\\\implies x = 2x + 4\\\implies -4 = 2x - x\\\implies x = -4$

From the second equation,

$4(5x - 2) = 2(9x + 3)\\\implies 20x - 8 = 18x +6\\\implies 20x - 18x - 8 -6 = 0\\\implies 2x -14 = 0\\\implies 2x = 14\\\implies x = \frac{14}{2} = 7$

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What is the remainder when 2 is synthetically divided into the polynomial

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Answer:

Step-by-step explanation:

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3 years ago

3(x+2)-2(×+1) i need help with this problem

zhuklara [117]

Question:

What is 3(x + 2) - 2(x + 1)?

Steps:

When you solve this type of equation always use the distributive property formula to solve this equation!

Formula: a(b + c) = ab + ac

So, what is 3(x + 2) ?

3x + 6

Also, what is -2(x + 1)?

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Then, put it back into the equation for you to solve this problem.

So, this would be the new equation:

3x + 6 - 2x - 2

Then, what you want to do is put variables next to each other and the numbers next to each other so it will be easier to simplify:

3x - 2x + 6 - 2

Then, simplify:

x + 4 is the answer!

Since 3x - 2x = x and 6 - 2 = 4

Hope that helped!!

~Serina

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3 years ago

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sveticcg [70]

2/3
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3 years ago

Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of

frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

3) $\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

4) $df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 21 37 58 116

Not Married 59 63 42 164

Total 80 100 100 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is $\alpha=0.05$

Part 2

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{80*116}{280}=33.143$

$E_{2} =\frac{100*116}{280}=41.429$

$E_{3} =\frac{100*116}{280}=41.429$

$E_{4} =\frac{80*164}{280}=46.857$

$E_{5} =\frac{100*164}{280}=58.571$

$E_{6} =\frac{100*164}{280}=58.571$

And the expected values are given by:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 33.143 41.429 41.429 116

Not Married 46.857 58.571 58.571 164

Total 80 100 100 280

And now we can calculate the statistic:

$\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

7 0

4 years ago

Could someone help me please

Rina8888 [55]

Answer:

the answer should be 30

Step-by-step explanation:

since you can divided 15 by 5 to get 3, you can multiply 10 x 3 to get 30

8 0

3 years ago

Solve the following 1) 2(x + 3) = x - 42) 4(5x-2) = 2(9x+3)PLS HELP ​

Solve the following 1) 2(x + 3) = x - 42) 4(5x-2) = 2(9x+3)PLS HELP