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4 years ago

Factor 25 into prime numbers

Mathematics

1 answer:

kirill [66]4 years ago

8 0

Image result for factor 25 into prime numbers

25 is a composite number, and it is 5 squared. 25 = 1 x 25 or 5 x 5. Factors of 25: 1, 5, 25. Prime factorization: 25 = 5 x 5, which can also be written 25 = 5².

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May someone help me with this plzzz

Anna71 [15]

Her book was 10 days late. D = days. The equation is .25(4) + .30d = 4.00. First you multiply .25 • 4 to get 1. Then you subtract 1 from both sides and get .30d = 3. Next you divide both sides by .30 to get d = 10.

8 0

3 years ago

Read 2 more answers

When I multiply 9x9 how would I go about counting by 9s?

11111nata11111 [884]

Answer:

If you're looking for a shortcut, I usually find the number 1 less than what you are multiplying 9 by, this case 8, and then add a number that gets to 9.

So 9x6 would be:

5+4=9

Step-by-step explanation:

When multiplying by 9s the product's two numbers added together =9.

Sorry if this is confusing. Hope this helps though.

5 0

3 years ago

What's the volume of the cone?

dmitriy555 [2]

V = (pi)r^2h / 3
= (pi)10^2(81) / 3
= (pi)(100)(81) / 3
= (pi)(8100) / 3
= (pi)2700

So C.

7 0

3 years ago

72-(63-8) and (72-63)-8

tatyana61 [14]

The Priority is always to parenthesis. It means that in both equations, begin by operating what's inside the parenthesis. Then Subtract what's left.

For the first one you get:
$72 - (63-8)$
$72 - 55$
$17$

For the second one you get:
$(72-63)-8$
$9-8$
$1$

Which mean that The 2 equations are not equal, because $17 \ \textgreater \ 1$
Hope this Helps! :D

3 0

3 years ago

Read 2 more answers

An article in Technometrics (Vol. 19, 1977, p. 425) presents the following data on the motor fuel octane ratings of several blen

Slav-nsk [51]

Answer:

$Median = 90.4$

$Q_1 = 88.6$

$Q_3 = 92.2$

Step-by-step explanation:

Given

The above data

Required

- A stem and leaf display

- The median

- The quartiles

First, determine the range of the data

$Smallest = 83.4$

$Highest = 100.3$

Next, group each dataset base on common whole numbers.

So, we have:

$83.4$

$84.3\ 84.3$

$85.3$

$86.7\ 86.7\ 86.7$

$87.4\ 87.5\ 87.6\ 87.7\ 87.8\ 87.9$

$88.2\ 88.3\ 88.3\ 88.3\ 88.4\ 88.5\ 88.5\ 88.6\ 88.6\ 88.7\ 88.9$

$89.0\ 89.2\ 89.3\ 89.3\ 89.6\ 89.7\ 89.8\ 89.8\ 89.9\ 89.9$

$90.0\ 90.1\ 90.1\ 90.1\ 90.3\ 90.4\ 90.4\ 90.4\ 90.5\ 90.6\ 90.7\ 90.8\ 90.9$

$91.0\ 91.0\ 91.0\ 91.1\ 91.1\ 91.1\ 91.2\ 91.2\ 91.2\ \ 91.5\ 91.6\ 91.6\ 91.8\ 91.8$

$92.2\ 92.2\ 92.2\ 92.3\ 92.6\ 92.7\ 92.7\ 92.7$

$93.0\ 93.2\ 93.3\ 93.3\ 93.4\ 93.7$

$94.2\ 94.2\ 94.4\ 94.7$

$96.1\ 96.5$

$98.8$

$100.3$

Next, we construct the stem and leaf plot.

The whole numbers will be the stem while the decimal parts will be the leaf.

So, we have:

$\begin{array}{ccc}{Stem} & {} & {Leaf} & {83} & {|} & {.4} & {84} & {|} & {.3\ .3} & {85} & {|} & {.3} & {86} & {|} & {.7\ .7\ .7} & {87} &{|} & {.4\ .5\ .6\ .7\ .8\ .9} & {88} & {|} & {.2\ .3\ .3\ .3\ .4\ .5\ .5\ .6\ .6\ .7\ .9} &{89} & {|} & {.0\ .2\ .3\ .3\ .6\ .7\ .8\ .8\ .9\ .9} & {90} & {|} &{.0\ .1\ .1\ .1\ .3\ .4\ .4\ .4\ .5\ .6\ .7\ .8\ .9} & {91} &{|}&{.0\ .0\ .0\ .1\ .1\ .1\ .2\ .2\ .2\ .5\ .6\ .6\ .8\ .8} &{92} &{|} &{.2\ .2\ .2\ .3\ .6\ .7\ .7\ .7} \ \end{array}$

$\begin{array}{ccc} {93} & {|} & {.0\ .2\ .3\ .3\ .4\ .7} & {94} &{|} & {.2\ .2\ .4\ .7} &{96} & {|} & {.1\ .5} & {98} & {|} & {.8} & {100} &{|} &{.3} \ \end{array}$