Domain: -∞<x<∞
Range: -∞<x<∞
X-Intercept: x=0
Y-Intercept: y=0
Increasing on the interval of 0<x<∞
Decreasing on the interval of -∞<x<0

When A=0, the graph equals y=0
- When A is greater than 1, it makes the graph skinnier than f(x)=|x|
- When A is less than 1 but greater than 0, it makes the graph fatter than f(x)=|x|
- When A turns negative, it flips the graph upside down.

-When B is greater than 0, it translates the graph to the right
- When B is less than 0, it translates the graph to the left

When C is greater than 0, the graph moves upwards
When C is less than 0, the graph moves downwards

3 0

3 years ago

For some integer n, the first, the third and the fifth terms of an arithmetic sequence are respectively 3n, 5n – 6, and 11n + 8.

Mazyrski [523]

Answer:

a₄=8n+1= -39.

Step-by-step explanation:

1) if a₁=3n; a₃=5n-6 and a₅=11n+8, then it is possible to calculate the difference according to 0.5(a₅-a₃)=0.5(a₃-a₁). Then

2) 0.5(11n+8-5n+6)=0.5(5n-6-3n); ⇔ 6n+14=2n-6; ⇔ n= -5.

3) if n=-5, then the 4th term is:

$a_4=\frac{a_5+a_3}{2}; \ = > \ a_4=\frac{11n+8+5n-6}{2}=8n+1;$