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Alexxandr [17]
3 years ago
11

tell how to get the variable to be on one side of the equation by itself. 6n=72. 6=1.2a. 21/2x = 15 please explain

Mathematics
2 answers:
Vikki [24]3 years ago
7 0

#1 divide by 6n to both sides to get n by itself

#2 multiply both sides by 6/5a to get a by itself

#3 multiply both sides by 2/5x to get x by itself


When you have whole numbers (no decimals) you can divide. When you have numbers with decimals, convert them to fractions and multiply by the reciprocal to get the variable by itself.

skelet666 [1.2K]3 years ago
7 0
1.) you have to divide 6 on both sides to get the n by itself and it'll equal n=12.
2.) divide 1.2 on both sides and you'll get a=5
3.) divide 2.5 on both side and you'll get x=6
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7 Caterpillars

Step-by-step explanation:

14/2

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3 years ago
Lotteries are an important income source for various governments around the world. However, the availability of lotteries and ot
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Answer: 0.0473

Step-by-step explanation:

Given : The proportion of gambling addicts : p=0.30

Let x be the binomial variable that represents the number of persons are gambling addicts.

with parameter p=0.30 , n= 10

Using Binomial formula ,

P(x)=^nC_xp^x(1-p)^{n-x}

The required probability = P(x>5)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\=^{10}C_6(0.3)^6(0.7)^{4}+^{10}C_7(0.3)^7(0.7)^{3}+^{10}C_8(0.3)^8(0.7)^{2}+^{10}C_9(0.3)^9(0.7)^{1}+^{10}C_{10}(0.3)^{10}(0.7)^{0}\\\\=\dfrac{10!}{4!6!}(0.3)^6(0.7)^{4}+\dfrac{10!}{3!7!}(0.3)^7(0.7)^{3}+\dfrac{10!}{2!8!}(0.3)^8(0.7)^{2}+\dfrac{10!}{9!1!}(0.3)^9(0.7)^{1}+(1)(0.3)^{10}\\\\=0.0473489874\approx0.0473

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5 0
3 years ago
What is the Inverse Equation<br><br>f(x) =6x-1 ?? please I need help!​
Scrat [10]

Answer:

f^{-1}(x)=\frac{x+1}{6}

Step-by-step explanation:

So we have the function:

f(x)=6x-1

To find the inverse function, switch x and f(x), change f(x) to f⁻¹(x), and solve for f⁻¹(x). Therefore:

f(x)=6x-1

Switch:

x=6f^{-1}(x)-1

Add 1 to both sides:

x+1=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{x+1}{6}

And that's our answer :)

5 0
3 years ago
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Fudgin [204]
You can’t solve this, not enough information
5 0
3 years ago
Find two positive numbers so that twice their sum equals their product and one number is 10 times the other number. Enter the sm
Softa [21]

Answer:

Step-by-step explanation:

We'll call the 2 numbers x and y. Starting with the last part of that first sentence "one number is 10 times the other number" can be written, in algebraic form:

y = 10x

Now on to the first statement about the numbers: "twice their sum" is 2(x + y) and "equals their product" is = xy. Putting that all together:

2(x + y) = xy and we know that y = 10x so

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2(11x)=10x^2 and

10x^2-22x=0 and

x(10x - 22) = 0 so

x = 0 or 10x - 22 = 0 which makes

x equal to \frac{22}{10}=2.2

So x = 2.2 and y = 22.

7 0
3 years ago
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