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3 years ago

Can somebody please help me and tell me how did you get the answer please thank you!!!

Mathematics

1 answer:

Aneli [31]3 years ago

7 0

Answer:

Step-by-step explanation:

(6x-5)+(12x+5)=180

18x=180

x=10

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When a figure is translated, its orientation remains the same or changes ?

Leviafan [203]

No it does not change it is a imaginary like used to move a figure. Nor does it move when it is rotated

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3 years ago

Use natural logarithms to solve the equation. Round to the nearest thousandth. 6e4x - 2 = 3

frosja888 [35]

6 · e^(4x - 2) = 3
   e^(4x - 2) = .5
ln e^(4x - 2) = ln (.5)
4x - 2 = ln (.5)
   4x = ln (.5) + 2
   x = (ln (.5) + 2)/4
   x = 0.3267
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Answer: B

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2 years ago

A group of restaurant owners surveyed a list of people to determine how preferences of meats compared to preferences of grains,

VashaNatasha [74]

There is no association between the chicken preferences and rice preferences. Option C

<h3>What is association?</h3>

There is an association between two variables when they both decrease or increase simultaneously. In many cases, the association between the variables can be shown using the correlation coefficient when the relationship is plotted on Cartesian coordinates.

If we look at the table, we can see that there is no association between the chicken preferences and rice preferences because because the proportion of chicken and rice eaters to all chicken eaters is lower than all rice eaters to all eaters; and because the proportion of chicken and rice eaters to all rice eaters is lower than all chicken eaters to all eaters.

Learn more about association:brainly.com/question/12782981

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1 year ago

(x+y)(x+6y) pls help me solve question pls and pls also give explanation if possible

steposvetlana [31]

Step-by-step explanation:

$= (x + y)(x + 6y)$

$= x \times x + x \times 6y + y \times x + y \times 6y$

$= {x}^{2} + 6xy + xy + 6 {y}^{2}$

$= {x}^{2} + 7xy + 6 {y}^{2}$

7 0

2 years ago

Find the derivative of <br> |x|/(x-1)

ki77a [65]

$\bf \cfrac{|x|}{x-1}\iff \cfrac{\sqrt{x^2}}{x-1}\iff \cfrac{(x^2)^{\frac{1}{2}}}{x-1}
\\\\\\
\textit{using the quotient rule}
\\\\\\
\cfrac{dy}{dx}=\cfrac{\frac{1}{2}(x^2)^{-\frac{1}{2}}\cdot 2x(x-1)-(x^2)^{\frac{1}{2}}\cdot 1}{(x-1)^2}$

$\bf \cfrac{dy}{dx}=\cfrac{\frac{x(x-1)-(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}}}{(x-1)^2}\implies \cfrac{dy}{dx}=\cfrac{x(x-1)-(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}(x-1)^2}
\\\\\\\cfrac{dy}{dx}=\cfrac{x(x-1)-|x|}{|x|(x-1)^2}$

4 0

3 years ago