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saveliy_v [14]
3 years ago
7

Mrs.Manning is making cookies for the bake sale. She jas 3/4 cup of flour and needs 1/3 cup of flour for her chocolate chip cook

ies. What fraction of the flour Mrs.Manning has will be used for her chocolate chip cookies?
Mathematics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:

<em>The fraction of the flour Mrs. Mannng will use for her chocolate chip cookies is 4/9</em>

Step-by-step explanation:

<u>Fraction of Portion</u>

Suppose we have a number n and another number m such as m>n. The portion or fraction of size n of m is given by the quotient n/m.

For example, 3 pieces of cake out of a total of 6 make them a fraction of 3/6 = 1/2 of the whole cake, i.e. half of the total available.

Mrs. Manning needs 1/3 cup of flour to make cookies for the bake sale. She actually has 3/4 cups of flour. Calculate the fraction of needed against the available flour:

\displaystyle \frac{\frac{1}{3}}{\frac{3}{4}}

The division can be easier performed by multiplying by the reciprocal of the denominator:

\displaystyle \frac{1}{3}\cdot \frac{4}{3}=\frac{1*4}{3*3}

\displaystyle =\frac{4}{9}

The fraction of the flour Mrs. Mannng will use for her chocolate chip cookies is 4/9

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Three to the power of negative two
Yanka [14]

Answer:

1/9

Step-by-step explanation:

3^-2 = 1/3^2

1/3^2 = 1/9

4 0
3 years ago
Solve for x. x/7 - y = a<br><br> Please help as soon as possible. Thanks! =D
ololo11 [35]

Hello!

Answer:

x=7(a+y)

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
Plleeaassee help it is URGENT MAATHH HELP PLEASE WILL GIVE 5 STARS ON ALL CORRECT ANSWERS, MARK AS BEST ANSWER AND SAY THANKS
lara [203]
Using Pythagoras in the first question
c=\sqrt{16 ^{2} + 4^{2} } =16.4924
which is approximately 16.5
for the second question
we also use Pythagoras
b^2=c^2-a^2
\sqrt{13^{2}-12^2}=5


4 0
3 years ago
Find the values of x and y that makes each equation true. –(5y)i+12=4x+25i
vovikov84 [41]

Equate real part and imaginary part:

LHS:

real part -- 12

imaginary part -- 5y

RHS:

real part = 4x

imaginary part = 25

Equating::

12 = 4x

x = 12/4

x = 3

Again:

5y = 25

y = 25/5

y = 5

So,

x = 3

y = 5

5 0
1 year ago
Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
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