Answer:
30
Step-by-step explanation:
Find the lowest number divisible by both 6, 5, and 2.
To start, let's list off the numbers divisible by six, and see if we can check any of them off for 5. Since both 2 and 6 are even numbers, we know that if a number is divisible by 6, it's divisible by 2.
6 12 18 24 30 36 42 48 54 60
All of these numbers are divisible by two. Let's find the lowest one that is divisible by 5. We know this by either the umber ending in 5 or 0.
30 is the lowest number that is divisible by 2, 5, or 6.
In simplest form (smallest possible answer) the ratio is equal to 2:3. But it is also equal to 4:6.
Well for the function of x we have x=t^5+1 and we know t= -1
So you plug in -1 instead of the t and you will get x=(-1)^5+1
Now just resolve that equation to get the value of x
x = (-1)^5+1 = -1+1 = 0 So x=0
Do the same with y and you’ll get y=2
Answer:
Option A
Step-by-step explanation:
We need to solve out ,
We can write it as ,
On simplyfing further,
On solving the above equation , we will get ,
Now we know that the value of modulus is never negative so when we will put x is equal to 2 on the RHS we will get -20 which is not possible . Therefore , the extraneous root is -2 .
<u>Option</u><u> </u><u>A </u><u>is </u><u>correct</u><u> </u><u>.</u>