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4 years ago

HELP! (37PTS)

Mathematics

2 answers:

kipiarov [429]4 years ago

8 0

Answer:

b. all real numbers

Step-by-step explanation:

The graphs of positive and negative x^2 parabolas will always have a domain of all real numbers. Even though you only have a portion of the graph and see a "restriction" on your domain values, it is incorrect to assume that the domain is limited to what you can see. As the branches of the parabola keep going up and up and up, the values of x keep getting bigger and bigger and bigger. Again, this is true for all + or - parabolas.

nata0808 [166]4 years ago

3 0

Answer:

The error is C and the solution is B

Step-by-step explanation:

C is because she didn't look left to right to see that is goes on forever

B because you look left and right to see

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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

3 years ago

200 labourers need 50 days to construct a road of 4 km long. How many labourers are needed to construct 8 km long in 80 days

patriot [66]

Answer:

250

Step-by-step explanation:

Number of labourers * Number of days worked = Total number of working days

Total number of working days to construct a 4km long road: $200*50=10000$

Total mumber of working days to construct a 8km long road: $10000*2=20000$

Labourers: 20000 ÷ 80 = 250.

250 labourers are required.

7 0

3 years ago

Please I don't Know Fractions

V125BC [204]

Answer:

11%

Step-by-step explanation:

1/3 (twix)

1/3 (snicker)

1/3 x 1/3 = 1/9

1/9 = .11

.11 = 11%

5 0

3 years ago

45 children attend preschool the number of two-year-olds is 1/2 the number of three-year-olds the number for your old is the sam

Mkey [24]

There are 9 two-year-olds and 18 each of 3 and 4 year olds.

To solve this we could write and solve the equation below, letting x be the number of 3 and 4 year olds.

x/2 + x + x = 45
x + 2x + 2x = 90
5x = 90
x = 18

From here, we just divide 18 by 2 to get the number of 2 year olds.

6 0

3 years ago

Help me please I think you have to find the area

abruzzese [7]

Answer:

I got B) ; 54m2

Step-by-step explanation:

the above diagram is a trapezium.

the area is gotten by; 1/2 (a+b)h

a = shortest side.

b = the longer side that is directly opposite to (a).

h = height.

1/2(3 + 9)9

1/2 by 12 by 9

to get 54

8 0

3 years ago