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OLga [1]
4 years ago
12

I’m not sure if my answer correct. If you can please help me.

Mathematics
2 answers:
artcher [175]4 years ago
8 0

Answer:

i think it correct

Step-by-step explanation:

zvonat [6]4 years ago
4 0

Answer:

The answer is

-  \frac{13}{15}  \\

Step-by-step explanation:

\frac{7z - 12}{6 {z}^{2} - 3z }  \\

z = - 2

Substitute the value of z that's - 2 into the above expression

We have

\frac{7( - 2) - 12}{6 ({ - 2})^{2}  - 3( - 2) }  =  \frac{ - 14 - 12}{6(4) + 6}  \\  =  \frac{ - 26}{24 + 6}   =  -  \frac{26}{30}

Reduce the fraction with 2

We have the final answer as

-  \frac{13}{15}  \\

Hope this helps you

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Suppose you are determining the growth rate of two species of plants. Species A is 12 cm tall and grows 2 cm per month. Species
SashulF [63]
The answer is
A(m) = 12 + 2m
B(m) = 10 + 3m

m - the number of months
F(m) - growth in a function of months m

Species A is 12 cm tall, so the number 12 is independent on a number of months. But it <span>grows 2 cm per month. This means that in m months it will grow 2 * m. So, its function is: A(m) = 12 + 2m

Similarly, s</span>pecies B is 10 cm tall, so the number 10 is independent on a number of months. But it grows 3 cm per month. This means that in m months it will grow 3 * m. So, its function is: B(m) = 10 + 3m
5 0
3 years ago
Please help solve this. t = -3. r = 4t^2 + 5
Andrei [34K]

Answer:

41

Step-by-step explanation:

replace the t with  -3:-

r = 4(-3)^2 + 5

=  36 + 5

= 41


7 0
3 years ago
Pls help with this question thank u all
drek231 [11]

Answer:

4 cm (A)

Step-by-step explanation:

triangle BAC is just a larger version of triangle EAD. given that ED is 5cm, and BC is 10cm, triangle BAC must be twice the size of EAD. since the ratio of AD to ED is 4:5, and BC is twice the size, all we need to do is multiply both sides by 2 to find length AC. 4*2 = 8. now we can subtract length AD from AC to get CD. 8 - 4 = 4.

sorry if what i wrote is a little confusing

3 0
3 years ago
Read 2 more answers
Which expression is equivalent to ((2a^-3b^4)^2(2a^5b)^-2)^-1?
tresset_1 [31]

Using the rules of exponents

\left(a^{b}\right)^{c}=a^{(b\cdot c)}\\a^{b}\cdot a^{c}=a^{(b+c)}

you can simplify this to

\left(2^{(2-2)}a^{(-3\cdot 2+5\cdot (-2))}b^{(4\cdot 2+1\cdot (-2))}\right)^-1\\\\=\left(2^{0}a^{-16}b^{6}\right)^{-1}\\\\=\dfrac{a^{16}}{b^{6}}

None of these answer choices matches the given expression.

8 0
3 years ago
Read 2 more answers
I know the value of x is congruent to the other side, confused about the square root part
Basile [38]

Answer:

  1. I think it is that I'm not sure

10 \sqrt{3}

8 0
3 years ago
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