Answer: Y=-5x+30
Step-by-step explanation:
First, you have to find the slope of graph so you find the rise over run Y/X. Since the X values are being measured by 1’s, and the Y values are being measure by 5’s, your slope would be -5 (not 5 as the graph line is decreasing therefore it is negative). To find b, you find the Y intercept of the graph (where Y is when X=0) and in this case, the y intercept is 30. So the equation that describes what is occurring in the graph is Y=-5x+30 as a linear equation is written as Y=mx+b. You can check If the equation is correct by substituting the x and y values of a specific coordinate point on the graph. For example: 25= -5(1)+30. This gives you 25=25 so the equation is correct.
D + q = 32....d = 32 - q
0.10d + 0.25q = 6.50
0.10(32 - q) + 0.25q = 6.50
3.20 - 0.10q + 0.25q = 6.50
-0.10q + 0.25q = 6.50 - 3.20
0.15q = 3.30
q = 3.30 / 0.15
q = 22 <=== 22 quarters
d + q = 32
d + 22= 32
d = 32 - 22
d = 10 <=== 10 dimes
Answer:
Step-by-step explanation:
Answer:
is it me or can I not see anything
Answer:
Step-by-step explanation:
We are given that 
is in <em>fourth</em> quadrant.
is always positive in 4th quadrant and
is always negative in 4th quadrant.
Also, we know the following identity about 
and 
:
Using \theta_1 in place of \theta:
We are given that 
is in <em>4th quadrant </em>so is negative.
So, value of
