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bogdanovich [222]
2 years ago
10

I need help with #7, I am not sure how to solve it and what interval means

Mathematics
1 answer:
Flura [38]2 years ago
8 0
Find solutions between the intervals
-3, -2, -1, 0, 1, 2, 3

You got the basic idea how to solve it but:

when you have 2^-3, it's not -8
2^-3 = 1/2^3 = 1/8
same goes with -2 and -1

When you have negative power you basically divide n^-x = 1/n^x
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The sum of two integers is 8 and their product is -20.<br>What are the integers?​
emmasim [6.3K]

Answer:

The answer to your question is

x = -2 and y = 10     or   x = 10 and y = -2

Step-by-step explanation:

          x + y = 8   (1)      from (1)    x = 8 - y

         xy = - 20    (2)

       

Solve them by substitution

      (8 - y) y = - 20

      8y - y² = -20

      y² - 8y - 20 = 0

   ( y - 10) (y + 2) = 0

    y - 10 = 0              and      y + 2 = 0

   <u> y1 = 10 </u>                               <u>y2 = -2</u>

 x1 = 8 - 10                             x2 = 8 - -2

 <u>x1 = -2</u>                                  <u> x2 = 10</u>

8 0
2 years ago
Someone please answer!
Yakvenalex [24]

Answer:

m = -2

Step-by-step explanation:

To find the slope of a line, use the equation:

m = y2 - y1 / x2 - x1

Then, substitute in values:

m = 54 - 58 / 2 - 0

m = -4 / 2

m = -2

6 0
2 years ago
Read 2 more answers
Wanni cycled 6 km from her house to the school at a uniform speed, v km/h. If she increased her speed
Karolina [17]

Answer:

The quadratic equation in terms of v is   v² + 2 v + 180 = 0

Step-by-step explanation:

Given as :

The distance between house to the school = d = 6 km

The uniform speed = v km/h

So, Time = \dfrac{\textrm Distance}{\textrm speed}

or, t = \dfrac{\textrm d}{\textrm v}

Or, t = \dfrac{\textrm 6}{\textrm v}

<u>Now, Again</u>

The speed is increase by 2 km/h

i.e speed = (v + 2) km/h

So, Time taken = t' = (t - \dfrac{4}{60})hours

i.e t' =  (t - \dfrac{1}{15})hours

Now, Time = \dfrac{\textrm Distance}{\textrm speed}

So, (t - \dfrac{1}{15}) = \dfrac{\textrm d}{\textrm v}

Or,  (t - \dfrac{1}{15}) = \dfrac{\textrm 6}{\textrm (v + 2)}

Or , \dfrac{\textrm 6}{\textrm v} -  \dfrac{1}{15} = \dfrac{\textrm 6}{\textrm (v + 2)}

Or , \dfrac{\textrm 90 - v}{\textrm 15 v} = \dfrac{\textrm 6}{\textrm v + 2}

Or, (90 - v) × (v + 2) = 6 × 15 v

Or, 90 v - 180 - v² - 2 v = 90 v

Or,  v² + 2 v + 180 = 90 v - 90 v

Or,  v² + 2 v + 180 = 0

So, The quadratic equation in terms of v

v² + 2 v + 180 = 0

Hence The quadratic equation in terms of v is   v² + 2 v + 180 = 0   Answer

3 0
3 years ago
Who gets this I am not sure what I have to do
natta225 [31]
Area of Parallelogram = base x height
height = 4.5 cm
base = 4.5 cm x 2

height = 4.5 cm
base = 9 cm

9 cm x 4.5 cm = 40.50 cm^2
8 0
3 years ago
Read 2 more answers
What is the oppsite of 1/2
mr_godi [17]

Answer:

the reciprocal is 2/1

you just flip the denominator and numerator to get your reciprocal

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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