Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
The answer is No Solutions
Step-by-step explanation:
Since this is absolute value, we know the answer has to be positive, because distance has to be positive. We see it is negative, and that cannot be, so the answer is no solutions.
Answer:
a
Step-by-step explanation:
a
3rd one 10 x 6 x 6
hope this is right
