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mash [69]
3 years ago
6

A heart shaped chocolate box is composed of one square and two half circles. The total number of chocolates in the box is calcul

ated by adding the area of a square given by 4² and the area of a circle approximated by 3². The company plans to add a small additional box for a promotional campaign containing one row (2) of chocolates. If the total combined heart shape and small box contain 69 chocolates, which of these equations could be utilized to solve for the number of chocolates in the small box (2)?
1 point
4²+ 3² + 2 = 69
B. 4² – 3² + 2 = 69
4²+ 3² – 2 = 69
4² – 3²– 2 = 69
Mathematics
2 answers:
Scrat [10]3 years ago
7 0

Answer:

4²+3²+2=69

Step-by-step explanation:

alexandr1967 [171]3 years ago
4 0

Answer:

A

Step-by-step explanation:

FOR THOSE WITH "4x^2" AND "3x^2" IT WOULD BE 4x^2 + 3x^2 + 2x = 69

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if we have a geometric series with u1 = 2.1 and r= 1.06, what would the least value of n be such that Sn &gt; 5543?
bulgar [2K]

Answer:

  88

Step-by-step explanation:

Write the expression for the sum in the relation you want.

  Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)

  Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)

The relation we want is ...

  Sn > 5543

  35(1.06^n -1) > 5543 . . . . substitute for Sn

  1.06^n -1 > 5543/35 . . . .  divide by 35

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  n·log(1.06) > log(5578/35) . . . take the log

  n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n

The least value of n such that Sn > 5543 is 88.

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