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mash [69]
2 years ago
6

A heart shaped chocolate box is composed of one square and two half circles. The total number of chocolates in the box is calcul

ated by adding the area of a square given by 4² and the area of a circle approximated by 3². The company plans to add a small additional box for a promotional campaign containing one row (2) of chocolates. If the total combined heart shape and small box contain 69 chocolates, which of these equations could be utilized to solve for the number of chocolates in the small box (2)?
1 point
4²+ 3² + 2 = 69
B. 4² – 3² + 2 = 69
4²+ 3² – 2 = 69
4² – 3²– 2 = 69
Mathematics
2 answers:
Scrat [10]2 years ago
7 0

Answer:

4²+3²+2=69

Step-by-step explanation:

alexandr1967 [171]2 years ago
4 0

Answer:

A

Step-by-step explanation:

FOR THOSE WITH "4x^2" AND "3x^2" IT WOULD BE 4x^2 + 3x^2 + 2x = 69

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mixer [17]

Answer:

25 mins

Step-by-step explanation:

Harpeet worked -- x mins

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If Aiysha worked 50 mins, Harpeet worked:

2x = 50

x = 25 mins

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3 0
3 years ago
What is one third of 75
choli [55]
One third of 75 would be 25 because you divide 75÷3=25
7 0
3 years ago
What does 12 ÷3/4 equal? ​
djyliett [7]

Answer:

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Hope this helps, have a great day/night!

5 0
3 years ago
(15.2*0.25-48.51/14.7)/x=(13/44-2/11-5/66/2.50)1.2/(3.2+0.8(5.5-3.25)
goldfiish [28.3K]

Answer:

x = 41.67

Step-by-step explanation:

The above equation, would be simplified or divided into parts;

Therefore, the given equation becomes;

A/x = B/C

Where;

A = (15.2*0.25-48.51/14.7)

B = (13/44-2/11-5/66/2.50)1.2

C = 3.2+0.8(5.5-3.25)

x = unknown variable.

<u>Part A</u>

(15.2*0.25-48.51/14.7) = (15.2*0.25 - 3.3)

A = (3.8 - 3.3)

A = 0.5

<u>Part B</u>

(13/44-2/11-5/66/2.50)1.2 = (0.3 - 0.18 - 0.030) * 1.2

B = 0.09 * 1.2

B = 0.108

<u>Part C</u>

(3.2+0.8(5.5-3.25)

C = 4*(2.25)

C = 9

<em>Substituting the values into the equation, we have;</em>

0.5/x = 0.108/9

<em>Cross-multiplying, we have;</em>

9 * 0.5 = 0.108x

4.5 = 0.108x

x = 4.5/0.108

x = 41.67

6 0
2 years ago
A survey of middle school students asked: What is your favorite winter sport? The results are summarized below:Favorite Winter S
Annette [7]

Answer:

a) 31.38%

b) 28.44%

c) 33.33%

d) 73.46%

e) 53.89%

Step-by-step explanation:

<h3>(See picture attached for sub-totals) </h3>

a) What is the probability of selecting a student whose favorite sport is skiing?

P = 171/545 = 0.3138 = 31.38%

b) What is the probability of selecting a 6th grade student?

P = 155/545 = 0.2844 = 28.44%

c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?

P = 70/210 = 0.3333 = 33.33%

d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?

P = 155/211 = 0.7346 = 73.46%

e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?

P = 180/(171+163) = 180/334 = 0.5389 = 53.89%

7 0
3 years ago
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