Answer:
25 mins
Step-by-step explanation:
Harpeet worked -- x mins
Aiysha worked -- 2x mins
If Aiysha worked 50 mins, Harpeet worked:
2x = 50
x = 25 mins
Thenks and mark me brainliest :))
One third of 75 would be 25 because you divide 75÷3=25
Answer:
16.
Hope this helps, have a great day/night!
Answer:
x = 41.67
Step-by-step explanation:
The above equation, would be simplified or divided into parts;
Therefore, the given equation becomes;
A/x = B/C
Where;
A = (15.2*0.25-48.51/14.7)
B = (13/44-2/11-5/66/2.50)1.2
C = 3.2+0.8(5.5-3.25)
x = unknown variable.
<u>Part A</u>
(15.2*0.25-48.51/14.7) = (15.2*0.25 - 3.3)
A = (3.8 - 3.3)
A = 0.5
<u>Part B</u>
(13/44-2/11-5/66/2.50)1.2 = (0.3 - 0.18 - 0.030) * 1.2
B = 0.09 * 1.2
B = 0.108
<u>Part C</u>
(3.2+0.8(5.5-3.25)
C = 4*(2.25)
C = 9
<em>Substituting the values into the equation, we have;</em>
0.5/x = 0.108/9
<em>Cross-multiplying, we have;</em>
9 * 0.5 = 0.108x
4.5 = 0.108x
x = 4.5/0.108
x = 41.67
Answer:
a) 31.38%
b) 28.44%
c) 33.33%
d) 73.46%
e) 53.89%
Step-by-step explanation:
<h3>
(See picture attached for sub-totals)
</h3>
a) What is the probability of selecting a student whose favorite sport is skiing?
P = 171/545 = 0.3138 = 31.38%
b) What is the probability of selecting a 6th grade student?
P = 155/545 = 0.2844 = 28.44%
c) If the student selected is a 7th grade student, what is the probability that the student prefers ice-skating?
P = 70/210 = 0.3333 = 33.33%
d) If the student selected prefers snowboarding, what is the probability that the student is a 6th grade student?
P = 155/211 = 0.7346 = 73.46%
e) If the student selected is an 8th grade student, what is the probability that the student prefers skiing or ice-skating?
P = 180/(171+163) = 180/334 = 0.5389 = 53.89%