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Yuri [45]
3 years ago
13

Solve 2|x - 1| >= 10

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

               \bold{\underline{x\in(-\infty\,,\,-4\big>\cup\big

Step-by-step explanation:

\bold{2|x-1|\geqslant10}\\\\{}\ \div2\qquad\div2\\\\\bold{|x-1|\geqslant5}\\\\\bold {x-1\geqslant5\qquad\quad\vee\qquad x-1\leqslant-5}\\\\\bold {x\geqslant6\qquad\qquad\vee\qquad\ \ x\leqslant-4}\\\\\bold{\underline{x\in(-\infty\,,\,-4\big>\cup\big

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Hat is the position of 7 in the number 876,543? A. The ten-thousands place B. The hundreds place C. The tens place D. The thousa
Vesna [10]
As you can see in this diagram, the answer is A, the ten-thousands place.

7 0
3 years ago
Um can y’all help me :)) plsss
Phantasy [73]

Answer:

(0+3,1) (3+3,0) (3+3x4)

5 0
2 years ago
Please give a explanation :)<br> i will mark as brainliest!!
Fynjy0 [20]

Answer:

x=12 y=3

Step-by-step explanation:

Since the scale factor is 1:3, that means that the length and width of Q multiplied by 3 gives the corresponding length and width of P.

Similarly, the length and width of P divided by 3 gives the corresponding length and width of Q.

With this, 9/3=3, which is the value of y.

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5 0
3 years ago
A cube has a volume of greater than 123 cm3. What are the possible lengths of the side of that cube?
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4 0
3 years ago
Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-620=\dfrac{749-620}{70-30}(x-30)

y-620=\dfrac{129}{40}(x-30)

y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)

y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}

Adding 620 on both sides, we get

y=\dfrac{129}{40}x-\dfrac{387}{4}+620

y=\dfrac{129}{40}x+\dfrac{2480-387}{4}

y=\dfrac{129}{40}x+\dfrac{2093}{4}

We need to find the y-value for x=57.

y=\dfrac{129}{40}(57)+\dfrac{2093}{4}

y=183.825+523.25

y=707.075

y\approx 707.1

Therefore, the required linear equation for the given situation is y=\dfrac{129}{40}x+\dfrac{2093}{4} and the average score for persons taking a 57-hour review course is 707.1.

4 0
2 years ago
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