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marysya [2.9K]
3 years ago
12

Write the point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5)?

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

The point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5) is y + 1 = 6x + 18

<u>Solution:</u>

Given, two points are (-3, -1) and (-2, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

<em><u>The slope of line "m" is given as:</u></em>

\text { slope of line } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }

Now, let us find the line equation using point slope form

y-y_{1}=m\left(x-x_{1}\right)

where m is slope

\begin{array}{l}{\text { Then, line equation } \rightarrow y-(-1)=6(x-(-3))} \\\\ {\rightarrow y+1=6(x+3)} \\\\ {\rightarrow y+1=6 x+18}\end{array}

Hence the point slope form is y + 1 = 6x + 18

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Answer:

15

Step-by-step explanation:

2(2) - 18 = -14 |-14| = 14

3(2) -7 = -1 |-1| = 1

14+1=15

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is 2 and 17

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Explain how to simplify this expression:
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11a+2

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(7a+9)+(4a−7)

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3 years ago
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Who packed all the pies? Kane’s bakery makes four flavour pies. The weight of each flavour pie is follows:
svet-max [94.6K]
This is an identical problem answered by myself a few days ago.  The answer is reproduced below for your convenience.

It is a very difficult problem if the box sizes are smaller or if there are more pies to pack.
For this particular problem, we first calculate the total weight of pies:
4 apple pies at 700 g = 2800 g
8 banoffee pies at 725 g =5800 g
3 custaard pies at 600 g = 1800 g
5 rhubarb pies at 675 g = 3375 g
for a total of 13775 g

The minimum number of boxes needed will be 13775/4000=3.44, or at least 4 boxes will be required.

We also note that 4 boxes will hold 16000 g, and we only need to pack 13775g, so there is a lot of margin.

We can proceed to do the mechanical way, fill in order of apple, banoffee, custard, and finally rhubarb pies.Following table shows how we fill, naively:      box content               Remaining to pack
Box A B C R     Weight    A B C R   
0                                      4  8  3 5     (original order)
1     4  1  0 0     3525       0  7  3 5
2     0  5  0 0     3625       0  2  3 5
3     0  2  3 0     3250       0  0  0 5
4     0  0  0 5     3375       0  0  0 0
Total weight     13775 g

So that does the job, 4 boxes (minimum) with none exceeding 4000 g to pack a total of 13775 g of pies.
 
Brainly - brainly.com/sf/question/8898504
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