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marysya [2.9K]
3 years ago
12

Write the point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5)?

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

The point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5) is y + 1 = 6x + 18

<u>Solution:</u>

Given, two points are (-3, -1) and (-2, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

<em><u>The slope of line "m" is given as:</u></em>

\text { slope of line } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }

Now, let us find the line equation using point slope form

y-y_{1}=m\left(x-x_{1}\right)

where m is slope

\begin{array}{l}{\text { Then, line equation } \rightarrow y-(-1)=6(x-(-3))} \\\\ {\rightarrow y+1=6(x+3)} \\\\ {\rightarrow y+1=6 x+18}\end{array}

Hence the point slope form is y + 1 = 6x + 18

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Use the linear combination method to solve the system of equations. Justify each step of your solution. If steps are not explain
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y=7

x=-7

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2(-3x - 7y )= 2(-28)

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Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5?
Mrrafil [7]

Answer:

The difference is a binomial with a degree of 6

Step-by-step explanation:

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a^3b + 9a^2b^2 − 4ab^5 and a^3b − 3a^2b^2 + ab^5

Let A = a^3b + 9a^2b^2 - 4ab^5

B= a^3b - 3a^2b^2+ab^5

The difference between A and B is

A - B = a^3b + 9a^2b^2 - 4ab^5 - (a^3b - 3a^2b^2 + ab^5)

Open parenthesis

A - B= a^3b + 9a^2b^2 - 4ab^5 - a^3b + 3a^2b^2 - ab^5

= a^3b - a^3b + 9a^2b^2 + 3a^2b^2 - 4ab^5 - ab^5

= 12a^2b^2 - 5ab^5

The fist term 12a^2b^2 has 2+2=4 as a degree

The second term 5ab^5 has 1 +5 =6 as a degree

Therefore,

the answer is: The difference is a binomial with a degree of 6

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Please help!! <br> Solve the system using an augmented matrix. Show all work
marishachu [46]

Answer:

<em>The solution of the system is:  x=2, y=5</em>

Step-by-step explanation:

The given system of equations is.......

-x-3y=-17\\ \\ 2x-6y=-26

So, the augmented matrix will be:   \left[\begin{array}{cccc}-1&-3&|&-17\\2&-6&|&-26\\\end{array}\right]

Now, we will transform the augmented matrix to the reduced row echelon form using row operations.

<u>Row operation 1 :</u>  Multiply the 1st row by -1. So..........

\left[\begin{array}{cccc}1&3&|&17\\2&-6&|&-26\\\end{array}\right]

<u>Row operation 2:</u>  Add -2 times the 1st row to the 2nd row. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&-12&|&-60\\\end{array}\right]

<u>Row operation 3:</u>  Multiply the 2nd row by -\frac{1}{12}. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&1&|&5\\\end{array}\right]

<u>Row operation 4:</u>  Add -3 times the 2nd row to the 1st row. So........

\left[\begin{array}{cccc}1&0&|&2\\0&1&|&5\\\end{array}\right]

Now, from this reduced row echelon form of the augmented matrix, we can get that x=2 and y=5

So, the solution of the system is:  x=2, y=5

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