The point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5) is y + 1 = 6x + 18
<u>Solution:</u>
Given, two points are (-3, -1) and (-2, 5)
We have to find that a line that passes through the given two points.
First let us find the slope of the line that passes through given two points.
<em><u>The slope of line "m" is given as:</u></em>


Now, let us find the line equation using point slope form

where m is slope

Hence the point slope form is y + 1 = 6x + 18