Ask question

Ask question

All categories

3 years ago

15

In triangle MNO, MN = 20 units, NO = 15 units, and MO = 18 units. What is the approximate difference between the largest and sma

llest angle measures?
2°
5°
14°
28°
(use law of cosines!!)

2 answers:

nikdorinn [45]3 years ago

7 0

Answer: It's not A or C it have to be out of B or D

Step-by-step explanation:

andreev551 [17]3 years ago

3 0

Hope this helps you.

You might be interested in

The radius of a cylinder is 7 c m and its height is 10 c m. Find curved surface area and volume.

erma4kov [3.2K]

Answer:

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

$\\$

To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

<em>Substituting the required values: </em>

$\\$

$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

<em>Substituting the required values, </em>

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

CSA of the cylinder = 440 sq. cm

Volume of the cylinder = 1540 cu. cm

8 0

2 years ago

Read 2 more answers

What is the product (2x-1)(x+4)

Ostrovityanka [42]

2x(x+4)-1(x+4)
2x^2+8x-x-4
2x^2+7x-4

8 0

3 years ago

Read 2 more answers

JL is a common tangent to circles M and K at point J. If angle MLK measures 61ᵒ, what is the length of radius MJ? Round to the n

Sladkaya [172]

3.122

The process to getting this comes in many steps. Firstly, you need to find the angles for JLK and MLJ. To find JLK use the arcsin function using the opposite side and the hypotenuse.

Arcsin(Opp/Hype) = JLK
Arcsin(.5) = JLK
30 degrees = JLK

This means MLJ = 31 degrees since they add up to 61 degrees.

Now we need to find the length of LJ, which we can do using the Pythagorean Theorem.

3^2 + JL^2 = 6^2
9 + JL^2 = 36
JL^2 = 27
JL = $\sqrt{27}$

Now that we have the angle of MLJ and the length of JL, we can use the tangent function to find MJ.

Tan(angle) = opp/adj
Tan(31) = MJ/ $\sqrt{27}$
$\sqrt{27}$ Tan(31) = MJ
3.122 = MJ

7 0

3 years ago

Read 2 more answers

100 POINTS pre-calc

Salsk061 [2.6K]

Answer:

you got this don't freak out

8 0

2 years ago

Julia wrote 20 letters each month for y months in a row. Write an expression to show how many total letters Julia wrote.

scoundrel [369]

The expression would be 20y

7 0

2 years ago