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4 years ago

Is 43 a multiple of seven

Mathematics

2 answers:

Alexeev081 [22]4 years ago

4 0

Answer:

43 is not a multiple of 7. The reason we know this is because 7 does not divide evenly into 43.

Step-by-step explanation:

Elanso [62]4 years ago

3 0

No, it is not. Nothing multiplied by 7=43

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F(x)=x^6+5x^5-x^3+x-6 divided by x+1

DochEvi [55]

No sloutions found for that

6 0

3 years ago

11 less than twice a number is 5

igomit [66]

Answer:

2x - 11 = 5

Step-by-step explanation:

x can be any variable

3 0

4 years ago

Read 2 more answers

Brad sold candy bars and cookies for a fundraiser at school. Candy bars sold for $3, and cookies sold for $5. He sold a total of

kari74 [83]

Answer: First option

12 candy bars were sold

Step-by-step explanation:

Call x the amount of candy sold and call z the amount of cookies sold. Then we know that

$x + z = 20$

We also know that candy bars sell for $ 3 and cookies sell for $ 5. The profit was $ 76

So:

$3x + 5z = 76$

To find the quantity of candy bars sold we must solve the system of equations:

$x + z = 20\\\\3x + 5z = 76$

Multiply the first equation by -5 and add it to the second equation

$-5x -5z = -100$

$3x + 5z = 76$

--------------------------------

$-2x = -24\\\\x = 12$

8 0

3 years ago

Read 2 more answers

A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a

UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

$P_{t}=P_{0}+500t$

Where $P_{t}$ = Population after t years

$P_{0}$ = Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = $\frac{5000}{500}$

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = $\frac{15000}{500}$

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = $\frac{35000}{500}$

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

$T_{n}=T_{0}(1+\frac{r}{100})^{t}$

$T_{n}$ = Population after t years

$T_{0}$ = Initial population

t = time in years

For double once,

Population after t years = 10000

$10000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{10000}{5000}$

$(1.05)^{t}=2$

Take log on both the sides

$log(1.05)^{t}=log2$

tlog(1.05) = log2

t = $\frac{log2}{log1.05}$

t = 14.20 years

For double twice,

Population after t years = 20000

$20000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{20000}{5000}$

$(1.05)^{t}=4$

Take log on both the sides

$log(1.05)^{t}=log4$

tlog(1.05) = log4

t = $\frac{log4}{log1.05}$

t = 28.413 years

For double thrice

Population after t years = 40000

$40000=5000(1+\frac{5}{100})^{t}$

$(1.05)^{t}=\frac{40000}{5000}$

$(1.05)^{t}=8$

Take log on both the sides

$log(1.05)^{t}=log8$

tlog(1.05) = log8

t = $\frac{log8}{log1.05}$

t = 42.620 years

4 0

3 years ago

A certain model of automobile has its gas mileage (in miles per gallon, or mpg) normally distributed, with a mean of 28 mpg and

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

We are finding the probability, which is a percentage, of each of these intervals on our standard bell curve. In order to find this percentage, we need to find the z-score that provides this percentage. To find the z-score:

$z=\frac{x_i-\bar{x}}{\sigma}$ which is the number in question minus the mean, all divided by the standard deviation. We're first looking for the probability that the gas mileage on a certain model of car is less than 26 mpg.

To find this z-score:

$z=\frac{26-28}{4}=-.5$ Depending upon which table you look at for the z-score determines how you will find it. The z-score that measure from the value and to the left of it is what we need. This decimal is .3085375, or 30.8538%.

Onto b., which is for the percentage of cars that have gas mileage over 34 mpg. Find the z-score, and this time, we look to the right of the value for the percentage:

$z=\frac{34-28}{4}=1.5$ and to the right of 1.5 standard deviations we will find .0668072, or 6.68072%

Then finally c., which wants the probability that the gas mileage on one of these cars is greater than 22 but less than 34 mpg. To do this we have to find the z-scores of each and then do some subtracting. First the z-scores:

$z=\frac{22-28}{4}=-1.5$ The percentage of data that lies to the right of that z-score is .9331927

The z-score for the other value, 34, was already found as 1.5, having .0668072 of the data to the right of that z-score. We subtract the smaller from the larger to determine what's left in-between:

.9331972 - .0668072 = .86639, or as a percentage, 86.639% of the cars fall into this interval for gas mileage.

7 0

3 years ago