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3 years ago

What is 6 divided by 5.04 equal

Mathematics

2 answers:

krek1111 [17]3 years ago

8 0

Answer:

Your answer is 25/24

Step-by-step explanation:

or 1.19

or 1 4/21

Alika [10]3 years ago

5 0

The answer should be 1.19

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Simplify plz :3 <3 1+4(6p-9)

mixas84 [53]

Answer:

24p - 35

Step-by-step explanation:

Step 1: Distribute.

$1+4(6p-9)$
$1+(4)(6p) + (4)(-9)$
$1+24p -36$

Step 2: Combine like terms.

$(24p) + (-36+1)$
$24p - 35$

Therefore, the answer is 24p - 35! I hope this helped you.

5 0

2 years ago

Which expression is equivalent to –3 – 3x – 1 + x 2x – 4 –2x + 4 –2x – 4? 4 – 2x

Anna35 [415]

Answer:

you didn't give any options, I could simplify it... but that doesn't show which expression is equivalent.

Step-by-step explanation:

4 0

3 years ago

Find the slope of the line that passes through the points (-2,2) and (13,-7)

Sindrei [870]

Slope: $\frac{-7-2}{13+2}$

-7 - 2 = -9

13 + 2 = 15

Slope = $-\frac{9}{15}$

7 0

2 years ago

Read 2 more answers

Please help meeeeeee

My name is Ann [436]

Answer:

y = 32.0°

Step-by-step explanation:

Using the sine ratio in the right triangle

siny° = $\frac{opposite}{hypotenuse}$ = $\frac{9}{17}$ , hence

y = $sin^{-1}$ ( $\frac{9}{17}$ ) ≈ 32.0°

6 0

2 years ago

Solve the equation 4x^3 + 4x^2-x-1 = 0 given that -1/2 is a zero of f(x) = 4x^3 + 4x^2-x-1.

Sholpan [36]

Answer:

The solution of equation 4x^3 + 4x^2-x-1 = 0 given that -1/2 is a zero of f(x) = 4x^3 + 4x^2-x-1 is $\frac{-1}{2} \text { and } \frac{1}{2} \text { and }-1$

Solution:

Given, cubic equation $4 x^{3}+4 x^{2}-x-1=0$

And $\frac{-1}{2}$ is a zero of $f(x)=4 x^{3}+4 x^{2}-x-1$

We have to find the other two roots of the given quadratic equation.

Let the other two roots be a, b.

Now, we know that, sum of roots of cubic equation $=\frac{-x^{2} \text { coefficient }}{x^{3} \text { coefficient }}$

$\text { Then, } \frac{-1}{2}+a+b=\frac{-4}{4} \rightarrow a+b=-1+\frac{1}{2} \rightarrow a+b=\frac{-1}{2} \rightarrow(1)$

Now, product of roots of cubic equation $=\frac{-\text { constant value }}{x^{3} \text { coefficient }}$

$\begin{array}{l}{\text { Then, } \frac{-1}{2} \times a \times b=\frac{-(-1)}{4} \rightarrow \frac{-1}{2} \times a b=\frac{1}{4}} \\\\ {\rightarrow a b=-2 \times \frac{1}{4} \rightarrow a b=\frac{-1}{2}}\end{array}$