8 am at 0
8:18 at 4.5
8:48 at 7.5 miles ???
18 min = .3 hour
48 min = .8 hour
in first .3 hours speed = 4.5/.3 = 15 mph
in next .5 hours = speed = 3/.5 = 6 mph
average speed for the whole trip = 7.5 miles/.8 hours = 9.375 mph
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8
You start by finding the slope : y2 - y1 / x2 - x1
2 - 8 / 4 - (-16)
- 6 / 20
m = - 3 / 10
Point slope form : y - y1 = m( x- x1 )
You can pick either of the coordinates and substitute them in
POINT SLOPE FORM EQUATION : y - 8 = -3/10 ( x + 16 )
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.
Find the median of the data (30.5)
Find the median of the lower half and the median of the upper half.
Subtract these two values.
The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
27.5 40.5
40.5-27.5 = 13
The interquartile range is 13.
