From the equation, it looks like we can set up a triangle like this. One side is x and the other is x + 20 because the northbound car traveled 20 miles farther. The hypotenuse is 100 because they were 100 miles apart.
Next, we can use the Pythagorean Theorem to solve for x:
a² + b² = c²
x² + (x + 20)² = 100²
This simplifies to:
x² + x² + 40x + 400 = 10000
2x² + 40x = 9600
2x² + 40x - 9600 = 0
After that, we can divided each side by 2:
x² + 20x - 4800 = 0
Next, we have to factor:
(x - 60)(x + 80) = 0
x = 60, -80
Since we know that distance can't be negative, 60 is the valid answer in this case.
x = 60
x + 20 = 80
Using this information, we know that the westbound car traveled 60 miles and the northbound car traveled 80 miles.
According to the temperature changes, it is found that:
- On Tuesday, the temperature at Noon was of -28.5 ºF.
- On Wednesday, the temperature at Midnight was of -5.5 ºF.
- On Thursday, the change was of -11.8 ºF.
- On Friday, the temperature at Noon was of -4.5 ºF.
<h3>What is the temperature change?</h3>
- The temperature change during a period is given by the <u>temperature at the end of the period subtracted by the temperature at the start of the period</u>.
On Tuesday:
- At the start of the period, the temperature was of -17.5 ºF.
- The change was of -11 ºF.
Hence:



On Tuesday, the temperature at Noon was of -28.5 ºF.
On Wednesday:
- At the end of the period, the temperature was of 10 ºF.
- The change was of 15.5 ºF.
Hence:


On Wednesday, the temperature at Midnight was of -5.5 ºF.
On Thursday:
- At the end of the period, the temperature was of -24 ºF.
- At the start of the period, the temperature was of -12.2 ºF.
Hence:

On Thursday, the change was of -11.8 ºF.
On Friday:
- At the start of the period, the temperature was of -21.8 ºF.
- The change was of 17.3 ºF.
Hence:



On Friday, the temperature at Noon was of -4.5 ºF.
You can learn more about change at brainly.com/question/24313700
Answer:
-1/2
Step-by-step explanation:
Answer:
Oioj[
Step-by-step explanation:
Answer:
The equation of the line is 2 x - y + 5 = 0.
Step-by-step explanation:
Here the given points are A( 1, 7) & B( -3, - 1) -
Equation of a line whose points are given such that
(
) & (
)-
y -
=
( x -
)
i.e. <em> y - 7=
( x- 1)</em>
<em> y - 7 =
( x -1)</em>
<em> y - 7 = 2 ( x - 1) </em>
<em> y - 7 = 2 x - 2</em>
<em> 2 x - y + 5 = 0</em>
Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1) is 2 x - y + 5 = 0.