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allsm [11]
3 years ago
5

I would like to know what the axis of symmetry is for this question

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

x = –4

Step-by-step explanation:

x = –koef x / (2•koef x²)

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What are the coordinates of the endpoints of the midsegment for △XYZ that is parallel to XZ⎯⎯⎯⎯⎯ ?
Ksenya-84 [330]

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Step-by-step explanation:

In a triangle the segment which joining the mid points of two sides:

  • Parallel to the 3rd side
  • Its length is equal half the length of the 3rd side
  • It's called the mid-segment of the triangle

In Δ XYZ

∵ Vertex X is (0 , 7)

∵ Vertex Y is (2 , 5)

∵ Vertex Z is (0 , 1)

∵ The mid-segment of Δ XYZ is parallel to XZ

- The mid-segment intersects the other two sides of the Δ

  at their mid-points

∴ The mid-segment intersects XY and YZ at their midpoints

∴ The endpoints of the mid-segment are the midpoints of

   XY and YZ

The mid point of a segments whose endpoints are (x_{1},y_{1}) and (x_{2},y_{2}) is (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

∵ X = (0 , 7) and Y = (2 , 5)

∴ x_{1} = 0 and x_{2} = 2

∴ y_{1} = 7 and y_{2} = 5

∵ The mid point of XY = (\frac{0+2}{2},\frac{7+5}{2})

∴ The mid point of XY = (\frac{2}{2},\frac{12}{2})

∴ The mid point of XY = (1 , 6)

∵ Z = (0 , 1) and Y = (2 , 5)

∴ x_{1} = 0 and x_{2} = 2

∴ y_{1} = 1 and y_{2} = 5

∵ The mid point of ZY = (\frac{0+2}{2},\frac{1+5}{2})

∴ The mid point of ZY = (\frac{2}{2},\frac{6}{2})

∴ The mid point of ZY = (1 , 3)

∵ The endpoints of the mid-segment are the midpoints of

   XY and YZ

∴ The end points of the mid segments are (1 , 6) and (1 , 3)

The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)

Learn more:

You can learn more about the mid-point in brainly.com/question/5223123

#LearnwithBrainly

7 0
3 years ago
Please help solve 16+x=12
melamori03 [73]

Answer:

x=-4

Step-by-step explanation:

1. subtract 16 from both sides which leaves you left with

x=-4

3 0
3 years ago
Read 2 more answers
In ΔNOP, the measure of ∠P=90°, PO = 77, NP = 36, and ON = 85. What ratio represents the cosine of ∠N?
Usimov [2.4K]

Answer:

36:85

Step-by-step explanation:

Given the right angled triangle as shown in the attachment, the cos of angle N can be gotten by simply using the CAH method in SOH CAH TOA.

According to CAH

Cos∠N = Adjacent/Hypotenuse

Hypotenuse is the longest of the triangle |ON| = 85

Since the opposite side to ∠N is 77, the third side will be the Adjacent side.

Adjacent side will be |NP| = 36

Therefore:

Cos∠N = 36/85

The ratio that represents the cosine of ∠N is 36:85

3 0
3 years ago
PLEASE HELP WILL GIVE BRAINLEST
Vesna [10]
Protons is the answer that makes the most sense
6 0
3 years ago
Read 2 more answers
Write a quadratic function to model the vertical motion for each​ situation, given ​h(t) equals negative 16t squared plus v0t+h0
Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

5 0
3 years ago
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