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2 years ago

The circumference of Tyler's bike tire is 72 inches. What is the diameter of the tire?

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

5 0

Answer:

22.92993 or 22.91831...

Step-by-step explanation:

Diameter: circumference / pi ( 3.14 )

72 / 3.14 = 22.92993

72 / π = 22.91831...

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Abigail was skateboarding home when the wheel axle of her skateboard broke. She had already traveled two thirds of the way home

OverLord2011 [107]

Answer:

I think that her taking the skateboard is 4 times as fast as her walking.

Step-by-step explanation:

I got this because she traveled twice as long and twice as fast on the skateboard, so if you multiply it together, there u have it.

4 0

3 years ago

Simplify the expression -2/3 divided by 3 3/4

Vitek1552 [10]

Answer:

-8/45

I hope this helped!

Step-by-step explanation:

-2/3 ÷ 3 3/4

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3 years ago

Which of the following is a proportion? 9/12= 8/10 3/4= 9/12 6/8= 8/12 12/18= 9/16

solong [7]

Answer:

The proportion is 3/4=9/12

Step-by-step explanation: For proportions you need to write it in a ratio, after doing that, you look at the outside numbers on the ratio on this case it is 3 and 12, multiply that and you get 36, after that do the same with the inside numbers to get another 36.

4 0

2 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Find the value of x and y

mrs_skeptik [129]

Answer: y is 40 x is 60

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers