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faust18 [17]
4 years ago
15

How do you solve this?​

Mathematics
1 answer:
crimeas [40]4 years ago
8 0

Answer: 140

Step-by-step explanation:

If you substitute the two for 40 and then subtract it from 180° (the angle of the line) then you will get one 40°

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Help please
Natali5045456 [20]

Answer:

17 ± sqrt(337)

 -----------------------

     2

Step-by-step explanation:

Let a = shorter leg

b= longer leg = a+7

c = hypotenuse = 2a-5

We can use the Pythagorean theorem

a^2+b^2 = c^2

a^2 + (a+7)^2 = (2a-5)^2

(a+7)^2 = a^2 +7a +7a+49 = a^2 +14a +49

(2a-5)^2 = 2a*2a -10a -10a +25 = 4a^2 -20a +25

Substituting these into the equation

a^2 + (a^2 +14a +49) = (4a^2 -20a +25)

Combine like terms

2a^2 +14a +49 = 4a^2 -20a +25

Subtracting 2a^2 from each side

2a^2 -2a^2 +14a +49 = 4a^2-2a^2 -20a +25

+14a +49 = 2a^2 -20a +25

Subtract 14a from each side

-14a+14a +49 = 2a^2 -20a -14a+25

+49 = 2a^2 -34a +25

Subtract 49 from each side

49-49 = 2a^2 -34a +25-49

0 =  2a^2 -34a -24

Divide each side by 2

0/2 =  2/2a^2 -34/2a -24/2

0 = a^2 -17a -12

Using the quadratic formula

a=1  b= -17  c = -12

17 ±sqrt( (-17)^2 - 4(1)(-12))

----------------------------------

2(1)

 17 ± sqrt(337)

 -----------------------

     2

4 0
3 years ago
Read 2 more answers
I need some help, see the picture for the question. Solve for V
Andrei [34K]

Answer:

the answer is A) h=3V/(Pi*r^2)

Step-by-step explanation:

This question is asking to solve for h, the equation is allready solved for V.

to solve for h means to get h by itself on one side of the equation.

1) V=(1/3)*pi*r^2*h. Divide 1/3*pi*r^2 to the other side of the equation

2) V/(1/3)*pi*r^2=h. 1/3 on the bottom denominator means we can multiply the reciprocal to the bottom and the top and get an equivalent answer. In short, move the 3 from the 1/3 onto the top.

3) (3*V)/(pi*r^2)=h. Simplify.

4) 3V/(Pi*r^2)=h.

3 0
4 years ago
∆ABC, &lt;B=90 •<br>|AC|=50cm |BCI=14cm Find AB.​
Delvig [45]

Answer:

Step-by-step explanation:

AC = 50 cm

BC = 14 cm

Pythagorean theorem,

AB² + BC² = AC²

AB² + 14² = 50²

AB² + 196 = 2500

AB² =  2500 - 196

AB² = 2304

AB = √2304

AB = 48 cm

8 0
3 years ago
How to do that? (Indices)<br><br> a<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \frac
Tamiku [17]
\bf a\cdot \cfrac{1}{2}\left(a+\cfrac{1}{a}  \right)\impliedby \textit{let's distribute first}&#10;\\\\\\&#10;\cfrac{a}{2}\left(a+\cfrac{1}{a}  \right)\implies \cfrac{a}{2}\cdot a+\cfrac{\underline{a}}{2}\cdot \cfrac{1}{\underline{a}}\implies \cfrac{a^2}{2}+\cfrac{1}{2}\implies \cfrac{a^2+1}{2}
3 0
3 years ago
A typical sugar cube has an edge length of 1 cm. If you had a cubical box that contained a mole of sugar cubes, what would its e
Mrac [35]
The answer is 8 × 10² km.

Volume of the cube with edge a is: V = a³
1 mole = V = a³
1 mole = 6.02 × 10²³ cm³
a = ?

a = ∛6.02 × 10²³ cm³ = 84 436 877 cm 
1 km = 1 000 000 cm
1 cm = 0.000001 km
a = 84 436 877 cm = 844 km = 8.44 × 100 km = 8.44 × 10² km ≈ 8 × 10² km
4 0
3 years ago
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