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yulyashka [42]
3 years ago
5

How to do that? (Indices) a

{1}{2} " alt=" \frac{1}{2} " align="absmiddle" class="latex-formula">(a+\frac{1}{a})
Mathematics
1 answer:
Tamiku [17]3 years ago
3 0
\bf a\cdot \cfrac{1}{2}\left(a+\cfrac{1}{a}  \right)\impliedby \textit{let's distribute first}
\\\\\\
\cfrac{a}{2}\left(a+\cfrac{1}{a}  \right)\implies \cfrac{a}{2}\cdot a+\cfrac{\underline{a}}{2}\cdot \cfrac{1}{\underline{a}}\implies \cfrac{a^2}{2}+\cfrac{1}{2}\implies \cfrac{a^2+1}{2}
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Need help! Not sure what exactly is going on here!
marishachu [46]

Answer:

idk

Step-by-step explanation:

4 0
4 years ago
The histogram below represents the high temperatures recorded each day over month period. Which of the following statements are
Kisachek [45]

Answer:

See possible solutions below.

Step-by-step explanation:

The statements are not given. But the following can be determined from the graph:

  • More days recorded temperatures between 82 and 84 then other temperatures.
  • The least number of days recorded temperatures between 88 and 90.
  • The histogram is skewed to the right also known as positive skewed distribution.
  • The mean and median will most likely be in the range of 82-84 temperatures. But the mean will be greater than the median.
4 0
3 years ago
1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)
Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that \mu = 8, \sigma = 1.5

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 8}{1.5}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 6.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.5 - 8}{1.5}

Z = -1

Z = -1 has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

7 0
3 years ago
What are the mean and the mode of the following set of data: 5, 12, 1, 5, 7
Alika [10]
Mean: so basically you add up all the numbers (5+12+1+5+7=30) and divide the sum (30) with how many numbers there are (5) so 30/5=6

mode: mode is numbers repeated, since there are two 5's it is the mode (you may also have multiple modes) 
3 0
3 years ago
Read 2 more answers
What is the avarege of -2.5,5.2,1.7 and -0.8
aleksandr82 [10.1K]

Average:

4.4 / 3 = 1.4666666666667

Count:

3

Sum:

4.4

Average:

4.4 / 3 = 1.4666666666667

Count:

3

Sum:

4.4

5 0
3 years ago
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