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melomori [17]
4 years ago
7

How many times larger is the value of 130000 than 130

Mathematics
2 answers:
Bezzdna [24]4 years ago
6 0
1000 times larger. Hope this helped! :)
stich3 [128]4 years ago
4 0
Well 130 x 1000 is 130,000
So it's 1000 times larger.
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It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many
aksik [14]
<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.

The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

8 0
3 years ago
If p(x) = x2 – 1 and 4(x) = 5(x-1), which expression is equivalent to (p -9)(x)?
jenyasd209 [6]

Answer:

5 times 5 24

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The circumference of a circle is 13π m. What is the area, in square meters? Express your answer in terms of π π.
Deffense [45]

Answer:

13×(22/7)whole square

4 0
3 years ago
Read 2 more answers
i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
Use a flowchart to prove if the triangles in each pair of similar. NO LINKS!!!<br>​
vekshin1

Answer:

Step-by-step explanation:

Start

<F = <Q                     Given

<GPF = <RPQ           Vertically opposite angles

<FGP = <QRP            A triangle has 180 degrees. 2 equal angles means the third pair must be equal

Triangle GPF ~ Triangle RPQ   AAA

end

I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.

20

JL/LE = 90/27                 Given

KL /LD = 90/27               Given

<JLK = <DLK                   Vertically opposite

Are the ratios equal       Yes  Then is the angle included Yes

Then the triangles are similar.

Are the ratios not equal  No then the triangles cannot be similar

Is the angle not included  Then similarity cannot be proved.

ΔJLK ≈ ΔDLK                  Equal Ratios and included angle === similarity

7 0
3 years ago
Read 2 more answers
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