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2 years ago

Write a sine function that has a midline of 3, an amplitude of 5 and a period of 2/7

Mathematics

1 answer:

Stells [14]2 years ago

7 0

sin(kx) has period 2π/k

so, you want

2 + 5sin(16π/7 x)

$hope \: its \: helpful \: to \: you$

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Russell randomly surveys seventh-graders in his school and finds that 6 of 30 attend summer camp. If there are 200 seventh-grade

Lady_Fox [76]

Answer:

Step-by-step explanation:

6 of 30 is the ratio 6 to 30 or 6/30.

6/30 reduces to 1/5

The survey shows that 1/5 of the students attend summer camp.

1/5 of 200 = 1/5 * 200 = 40

3 0

2 years ago

Answer this question thanks

9966 [12]

First add 3 to both sides (what you do on one side you must do to the other). Since 3 is being subtracted, addition (the opposite of subtraction) will cancel it out (make it zero) from the right side and bring it over to the left side.

2 < u - 3

2 + 3 < u - 3 + 3

5 < u - 0

5 < u

For the graph will you have a empty or colored in circle?

If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.

If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.

Which direction will the ray go?

If the variable is LESS then the number then the arrow will go to the left of the circle.

If the variable is MORE then the number then the arrow will go to the right of the circle.

In this case your inequality is:

5 5

aka 5 is less then u OR u is greater then 5

This means that the graph will have an empty circle and the arrow will go to the right of 5. Look at image below.

Hope this helped!

~Just a girl in love with Shawn Mendes

3 0

2 years ago

Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A

liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality $\sin ^2\theta +\cos ^2\theta \geq 1$

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

$\sin \theta$ = side opposite to $\theta$ /hypotenuse

$\cos \theta$ = side adjacent to $\theta$ /hypotenuse

$\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta$

$\cos \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta$

So, coordinates of A = $\left ( \cos \theta ,\sin \theta \right )$

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by $x^2+y^2=1$

Put $(x,y)=\left ( \cos \theta ,\sin \theta \right )$

$\cos ^2\theta +\sin ^2\theta =1$

So, $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ satisfies the equation $x^2+y^2=1$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ inside the circle, $\cos ^2\theta +\sin ^2\theta$

For points $(x,y)=\left ( \cos \theta ,\sin \theta \right )$ outside the circle, $\cos ^2\theta +\sin ^2\theta >1$

So, only points on the circle satisfy the given inequality.

4 0

2 years ago

Read 2 more answers

In the diagram below, one square unit represents 5 square meters. Find the area of the figure

seropon [69]

To get you started: Look at the bottom 4 white squares. Each square represents an area of 5 sq. meters. Thus, these 4 white squares represent an area of 4(5 sq m) = 20 sq m.

Use the same method to calculate the remaining area. Hint: I count 7 full squares in this "remaining area."

5 0

2 years ago

Read 2 more answers

Which percent is equivalent to 2 5/6 A. 2.56% B. 2.83% C. 256% D. 283.3

Katen [24]

2 5/6 = 17/6 = 2.833...to find the percent multiply the decimal by 100 and u get :
283.3% <==

6 0

3 years ago

Read 2 more answers