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Anastasy [175]
3 years ago
5

Why is this math answer wrong? Please help regarding natural logs?

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

\bf 7275(2^k)^3~~+~~5723\cdot 2^k~~+~~4725k(2^k)^3~~+~~3717k2^k~\hfill \begin{cases} n=2^k\\ k=\frac{ln(n)}{ln(2)}\\[-0.5em] \hrulefill\\ n=2^{\frac{ln(n)}{ln(2)}} \end{cases} \\\\[-0.35em] ~\dotfill

\bf 7275n^3~~+~~5223n~~+~~4725\cdot \cfrac{ln(n)}{ln(2)}(n^3)~~+~~3717\cfrac{ln(n)}{ln(2)}(n) \\\\\\ 7275\left( 2^{\frac{ln(n)}{ln(2)}} \right)^3+5273\left( 2^{\frac{ln(n)}{ln(2)}} \right)+4275\cfrac{ln(n)}{ln(2)}\left( 2^{\frac{ln(n)}{ln(2)}} \right)^3+3717\cfrac{ln(n)}{ln(2)}\left( 2^{\frac{ln(n)}{ln(2)}} \right)

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Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sisters birthday party. what is the largest number o
Vinil7 [7]

The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Given that Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sister's birthday party and asked to find out the largest numbers of snacks in the bag.

There are 24 jolly ranchers and 56 blow pops and For the maximum numbers of snacks in the bag can be 24 jolly ranchers and 56 blow pops.

The maximum numbers of snacks that can be filled in a snacks bag is 24 jolly ranchers and 56 blow pops.

Therefore,The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Learn more about numbers here:

brainly.com/question/17429689

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7 0
1 year ago
Jasmijn is a pet groomer. She charges n dollars to clip a dog's nails, w dollars to wash the dog and h dollars
lbvjy [14]

Answer:

4(n+w+h) and 4n+4w+4h

Step-by-step explanation:

If the price for each dog is n+w+h,

Then the price for 4 dogs would be 4 times the sum of n, w, and h:

4(n+w+h)

And can also be written as 4n+4w+4h using the distributive property.

7 0
3 years ago
A quarterback throws a football to a teammate. The football is 6.5ft above the ground when it leaves the quarterback's hand. His
sergejj [24]

Answer:

y = - 16t² + 55.6t + 6

Step-by-step explanation:

Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football

So y = y₀ + vt - 1/2 × (32 ft/s²)t²

y = y₀ + vt - 16t² where y₀ = 6.5 ft

y = 6 + vt - 16t²

Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have

5 = 6.5 + v(3.5 s) - 16(3.5 s)²

5 = 6.5 + 3.5v - 196

collecting like terms, we have

5 - 6.5 + 196 = 3.5v

194.5 = 3.5v

v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s

So, substituting v into y, our quadratic model is

y = 6 + 55.6t - 16t²

re-arranging, we have

y = - 16t² + 55.6t + 6

6 0
3 years ago
10-24
jasenka [17]

Answer:

Like this...

Step-by-step explanation:

The best represented graph should look something like this :)

(program used is Desmos)

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3 years ago
What fraction of 56 of 21?
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