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Mashcka [7]
3 years ago
10

Giving free brainliest to first correct response, what is 2+2+5+3+6+4+6+2+5+78+2+1?

Mathematics
2 answers:
KengaRu [80]3 years ago
4 0

Answer:

116

Step-by-step explanation:

Rom4ik [11]3 years ago
3 0

Answer:

116

Step-by-step explanation:

2+2+5+3+6+4+6+2+5+78+2+1

4+5+3+6+4+6+2+5+78+2+1

9+3+6+4+6+2+5+78+2+1

12+6+4+6+2+5+78+2+1

18+4+6+2+5+78+2+1

22+6+2+5+78+2+1

28+2+5+78+2+1

35+78+2+1

113+2+1

116

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Last year Chesa made 32 one-cup servings of soup for a school party. This year, she will make two times the amount of soup that
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64

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W^2-8w-20 factor the polynomial.
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Read 2 more answers
If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 477 viruses would d
melisa1 [442]

Answer:

0.01596

Step-by-step explanation:

A scientist claims that 8% of the viruses are airborne

Given that:

The population proportion p = 8%

The sample size = 477

We can calculate the standard deviation of the population proportion by using the formula:

\sigma_p = \sqrt{\dfrac{p(1-p)}{n}}

\sigma_p = \sqrt{\dfrac{0.8(1-0.8)}{477}}

\sigma_p = \sqrt{\dfrac{0.0736}{477}}

\sigma_p = 0.02098

The required probability can be calculated as:

P(| \hat p - p| >  0.03) = P(\hat p - p< -0.03 \ or \  \hat p - p > 0.03)

= P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} < -\dfrac{0.03}{0.0124}  \bigg ) +  P \bigg ( \dfrac{\hat p -p }{\sqrt{\dfrac{p(1-p)}{n}}} >\dfrac{0.03}{0.0124} \bigg )

= P(Z < -2.41) + P(Z > 2.41)

= P(Z < -2.41) + P(Z < -2.41)

= 2P( Z< - 2.41)

From the  Z-tables;

P(| \hat p - p| >  0.03) = 2 ( 0.00798

P(| \hat p - p| >  0.03) = 0.01596

Thus, the required probability = 0.01596

3 0
3 years ago
If Fernando paid $450 for a notebook that was 75% of the original price, what was the original price?
kotykmax [81]
450➗75✖100= 600. The original price was $600
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3 years ago
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