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stich3 [128]
3 years ago
10

How do you solve 2x+4y=7 and -2x +3y=14

Mathematics
1 answer:
Iteru [2.4K]3 years ago
7 0

Answer:

y=3    x= -5/2

Step-by-step explanation:

simultaneous equations

2x + 4y = 7  ------ eq 1

-2x + 3y = 14 --------eq2

(different signs add)

(eq 2 + eq 1)

-2x +(-2x) = 0

4y+3y = 7y

7+14 = 21

7y= 21

(divide both sides by 7)

y= 21/7= 3

2x + 4(3) = 7

2x+ 12=7

2x = 7-12

2x = -5

x= -5/2

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A test has 20 questions. if peter gets 80 percent correct, how many questions did peter miss?
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20=100%                             
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x=16  correct


20-16=4

answer

4=20%

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Which of the following isn't a composite number?<br><br> 33<br> 41<br> 51<br> 69
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3 years ago
A wire bonding process is said to be "in control" if the mean pull strength is 10 pounds. It is known that pull-strength measure
Degger [83]

Answer:

B. 0.0099

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this roblem, we have that:

\mu = 10, \sigma = 1.5, n = 4, s = \frac{1.5}{\sqrt{4}} = 0.75

Probability of being out of control.

Less than 8.25 pounds, which is the pvalue of Z when X = 8.25. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{8.25 - 10}{0.75}

Z = -2.33

Z = -2.33 has a pvalue of 0.0099.

So the correct answer is:

B. 0.0099

4 0
4 years ago
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