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Serjik [45]
2 years ago
14

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 3)2 = 16 in the manner described. (en

ter your answer as a comma-separated list of equations. let x and y be in terms of t.) (a) once around clockwise, starting at (4, 3). 0 ≤ t ≤ 2π.
Mathematics
1 answer:
sveticcg [70]2 years ago
5 0

Answer:

x(t) = 4 cos(-t)\\y(t) = 4 sin(-t) + 3\\

and t ∈ [0,2π]

Step-by-step explanation:

The standard equation for circle is:

(x-h) ^2 + (y-k)^2 = r^2

Comparing our equation with standard

x^2 + (y-3)^2 =16

h= 0,

k= 3

r= 4 (as in standard r², so r =√ r²)

Required:

Parametric equations of the circle

Formula:

x = r cos(t) + h\\y= r cos(t) +k

Putting values of r and h and k we get

x= 4 cos(t) + 0 \\x= 4 cost(t) \\y= 4 sin(t) + 3

As we need to start the object at (4,3)

x(0) = 4 and y(0) = 3

and the period is 2π

As the rotation is starting clock wise we will invert the value of t i.e -t

x(t) = 4 cos(-t)\\y(t) = 4 sin(-t) + 3\\

and t ∈ [0,2π]

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Answer:

2\frac{1}{6} pounds.

Step-by-step explanation:

We have been given that Gina's literacy bucket weighs 6 pounds. Her novel weighs 1 4/6 pounds, and her chrome book weighs 2 1/6.

To find weight of bucket after taking out the two items, we will subtract weight of each item from 6 pounds as:

\text{Weight of bucket}=6-1\frac{4}{6}-2\frac{1}{6}

Let us convert mixed fractions into improper fractions as:

1\frac{4}{6}=\frac{6\cdot 1+4}{6}=\frac{10}{6}\\\\2\frac{1}{6}=\frac{6\cdot 2+1}{6}=\frac{12+1}{6}=\frac{13}{6}

\text{Weight of bucket}=6-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{6\cdot 6}{6}-\frac{10}{6}-\frac{13}{6}

\text{Weight of bucket}=\frac{36}{6}-\frac{10}{6}-\frac{13}{6}

Combine numerators:

\text{Weight of bucket}=\frac{36-10-13}{6}

\text{Weight of bucket}=\frac{13}{6}

\text{Weight of bucket}=2\frac{1}{6}

Therefore, the weight of the bucket is 2\frac{1}{6} pounds.

6 0
3 years ago
Complete the sentence to show the distributive property of 7x6=
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Help please, I'm stuck on this :/
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Do you have a calculator? you can solve it by substituting x.

y=16x^2

0: y = 16(0)^2 = 16(0) = 0

(x = 0 , y = 0)

0.5: y = 16(0.5)^2 = 16(0.25) = 4

(x = 0.5 , y = 4)

1: y = 16(1)^2 = 16(1) = 16

(x = 1 , y = 16)

1.5: y = 16(1.5)^2 = 16(2.25) = 36

(x = 1.5 , y = 36)

2: y = 16(2)^2 = 16(4) = 64

(x = 2 , y = 64)

2.5: y = 16(2.5)^2 = 16(6.25) = 100

(x = 2.5 , y = 100)

3 : y = 16(3)^2 = 16(9) = 144

(x = 3 , y = 144)

4: y = 16(4)^2 = 16(16) = 256

(x = 4 , y = 256)

if you multiply a negative number by itself, it will become positive. So, -4, -3, -2.5, -2, -1.5, -1, -0.5 will be the same as the positive 4, 3, 2.5, 2, 1.5, 1, 0.5.

I'm not sure about the pattern, but if you graph it, it'll be symmetrical across the y-axis.

8 0
3 years ago
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