Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Try this option:
1. according to the condition Kris scored '2x' points, Julio did 'x' points (Kris scored 2 times as many points as Julio).
2. according to the condition Kris'_points+Julio's_points=36_points. It means, that x+2x=36.
3. If to solve this equation (2x+x=36), then Julio scored x=12 points, Kris scored 2x=12*2=24 points.
answer: 12 (Julio); 24 (Kris).
Answer:
the correct answer is A, thats when cos of ttheta is
Answer:

Step-by-step explanation:
First, rewrite the given equation in the form of y=mx+c.
m is the gradient while c is the y-intercept.
3x-5y=8
5y= 3x -8

Thus, the gradient of the given equation is ⅗.
The product of the gradients of perpendicular lines is -1.
(gradient of line)(⅗) = -1
gradient of line= -1 ÷⅗
gradient of line= 

To find the value of c, substitute a coordinate.
When x=3, y=7,

7= -5 +c
c= 7+5
c= 12
Hence, the equation of the line is
.