2 years ago

Please help please and thank you

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

3 0

Step-by-step explanation:

$\text{We know:}\\\\\sin(-\alpha)=-\sin\alpha\\\\\sin(\alpha\pm k\cdot360^o)=\sin\alpha\\\\===============================\\\\\sin(360^o-\theta)=\sin\bigg(-(\theta-360^o)\bigg)=-\sin(\theta-360^o)=-\sin\theta$

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