Answer:
13,57,31
Step-by-step explanation:
Given that X, Y , Z be three random variables which satisfy the following conditions:
Var(X) = 4, Var(Y ) = 9, Var(Z) = 16. Cov(X, Y ) = −2, Cov(Z, X) = 3,
Var(y,z) =0 since given as independent
To find
b)
c) Var(X + Y + Z)
Note:
Var(x+y) = var(x) + Var(Y) +2cov (x,y)
Var(x+2y) = Var(x) +4Var(y)+4cov (x,y)
3, 15 and 30
Let the first number be x
Second number is 5 times the first number = 5x
Third number is twice the second number = 2×5x = 10x
The equation becomes;
x + 5x + 10x = 48
16x = 48
x = 48 ÷ 16
x = 3
Therefore the three numbers are x = 3, 5x = 15 and 10x = 30
This answer is A
A. X= -1
-1 is equal to-1
Hope it helps