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lidiya [134]
3 years ago
7

How to simplify this problem: (4c^4)^3

Mathematics
1 answer:
hjlf3 years ago
7 0

Answer:

64c^12

Step-by-step explanation:

(4c^4)^3 distribute exponents

{(4)^3 (C^12)} simplify

64c^12

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Help asap pleaseeeeeeeeee its due 5 and its 4 for me right now
Gre4nikov [31]

Answer:

The answer would be A

Step-by-step explanation:

1^2=1×1= 1

2^2 =2×2=4

3^2=3×3=9

4^2=4×4=16

Therefore,

√11  lies between 3 and 4

8 0
2 years ago
Read 2 more answers
StartFraction 4 over 2 EndFraction = StartFraction 5 over x EndFraction
KATRIN_1 [288]

Answer:

x = 2.5

Step-by-step explanation:

<em>For the equation:</em>

<em />\frac{4}{2} = \frac{5}{x}

<em>The cross product is:</em>

4 × x = 2 × 5

<em>Solving for X</em>

<em />x = \frac{2 * 5}{4}<em />

<em />

<em>And reducing:</em>

x = 2.5

3 0
3 years ago
Read 2 more answers
A goat is grazing outside of a rectangular barn that has dimensions 20 ft by 30 ft.
MariettaO [177]

Answer:

  • 108π  ft² or  339.29 ft²

Step-by-step explanation:

<em>Refer to attached picture.</em>

<u>The grazing area of the goat is 3/4 of area of circle with 12 ft radius:</u>

  • A = 3/4(πr²) = 3/4(π*12²) = 108π  or  339.29 ft²

5 0
3 years ago
Jack has some marbles. He has ten more red marbles than blue marbles. He has fewer yellow marbles than blue marbles.
kap26 [50]

Answer:

<u>Jack has at least 15 marbles: 12 red, 2 blue and 1 yellow.</u>

Step-by-step explanation:

1. Let's review the information given to us to solve the problem correctly:

Number of red marbles = 10 more than blue marbles

Number of yellow marbles fewer than blue marbles

2. How many of each color marble could Jack have?

r = Number of red marbles

b = Number of blue marbles

y = Number of yellow marbles

r = b + 10

y < b

If y = 1, then b ≥ 2, and r = b + 10,

fulfilling the three conditions, we have:

<u>y = 1, b = 2, and r = 12</u>

5 0
3 years ago
Help needed please im stuck
defon

Answer:

  a) b^3

  b) x^3

Step-by-step explanation:

It can be helpful to think of the exponent as specifying the number of times the base is a factor in the product. Of course, common factors in the numerator and denominator cancel.

<h3>a)</h3>

  \dfrac{b^7}{b^4}=\dfrac{b\cdot b\cdot b\cdot b\cdot b\cdot b\cdot b}{b\cdot b\cdot b\cdot b}=b\cdot b\cdot b=b^{7-4}=\boxed{b^3}

__

<h3>b)</h3>

  \dfrac{x\cdot x^5}{x^2\cdot x}=\dfrac{x\cdot x\cdot x\cdot x\cdot x\cdot x}{x\cdot x\cdot x}=x\cdot x\cdot x=x^{6-3}=\boxed{x^3}

4 0
2 years ago
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