Question

1. Graph the six terms of a finite series where a1 = 5 and r = 1.25.

Answer 1

Step-by-step explanation:

This series is in Geometric Progression, with initial term, a₁, as 5 and common ratio, r, as 1.25

Geometric growth can be represent by exponential growth function. Exponential growth for this scenario will be,

$f(n)=a_1(r)^{n-1}$

Putting values of n, we get the series as

$=5,6.25,7.81,9.77,12.21,15.26$

So the points on the graph will be,

$\left(1,5\right),\left(2,6.25\right),\left(3,7.81\right),\left(4,9.77\right),\left(5,12.21\right),\left(6,15.26\right)$

The graph is attached below.

Answer 2

For the answer to the question above, asking to graph the six terms of a finite series where a1 = 5 and r = 1.25.
I'll provide the answer with the solutions below.
a1 = 5 
a2 = 5*r = 5*(5/4) = 25/4 
a3 = 5*r² = 5*(5/4)² = 125/16 
a4 = 5*r³ = 5*(5/4)³ = 625/256 
a5 = 5*r⁴ = 5*(5/4)⁴ = 3125/1024
I hope this helps