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3 years ago

1. Graph the six terms of a finite series where a1 = 5 and r = 1.25.

Mathematics

2 answers:

leva [86]3 years ago

8 0

Step-by-step explanation:

This series is in Geometric Progression, with initial term, a₁, as 5 and common ratio, r, as 1.25

Geometric growth can be represent by exponential growth function. Exponential growth for this scenario will be,

$f(n)=a_1(r)^{n-1}$

Putting values of n, we get the series as

$=5,6.25,7.81,9.77,12.21,15.26$

So the points on the graph will be,

$\left(1,5\right),\left(2,6.25\right),\left(3,7.81\right),\left(4,9.77\right),\left(5,12.21\right),\left(6,15.26\right)$

The graph is attached below.

rodikova [14]3 years ago

3 0

For the answer to the question above, asking to graph the six terms of a finite series where a1 = 5 and r = 1.25.
I'll provide the answer with the solutions below.
a1 = 5
a2 = 5*r = 5*(5/4) = 25/4 
a3 = 5*r² = 5*(5/4)² = 125/16 
a4 = 5*r³ = 5*(5/4)³ = 625/256 
a5 = 5*r⁴ = 5*(5/4)⁴ = 3125/1024
I hope this helps

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Nick randomly selects a digit from the set { 0 , 1 , 2 , . . . , 9 } and a letter from the set { A, B, C, . . ., Z } . Matthew w

Alex787 [66]

Answer: 259/260 or 0.99615 (depending on which answer format your teacher wants)

There are 10 numbers in the set {0, 1, 2, ..., 9}. There are 26 letters in the set {A, B, C, ..., Z}. Multiply those values: 10*26 = 260. So there are 260 ways to pick a number followed by a letter. One example is 7P.

There is only one way Matthew can get the correct answer, and there are 260 - 1 = 259 ways to get the wrong answer. We divide 259 over 260 to get the probability of getting the incorrect answer, which is 259/260.

If you need this fraction in decimal form, then use a calculator to find that 259/260 = 0.99615 approximately

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2 years ago

Value of x in 2x-7=35 is

Reika [66]

Answer:

x=21

Step-by-step explanation:

2x - 7 = 35

+7 +7

-----------------

2x = 42

----- -----

2 2

x = 21

The answer is 21, hope this helps.

4 0

3 years ago

Read 2 more answers

A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an a

Scrat [10]

Answer:

The answer is (C) 8

Step-by-step explanation:

First, let's calculate the length of the side of the square.

$A_{square}=a^2$ , where $a$ is the length of the side. Now, let's try to build the square. First we need to find a point which distance from (0, 0) is 10. For this, we can use the distance formula in the plane:

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ which for $x_1=0$ and $y_1 = 0$ transforms as $d=\sqrt{(x_2)^2 + (y_2)^2}$ . The first point we are looking for is connected to the origin and therefore, its components will form a right triangle in which, the Pythagoras theorem holds, see the first attached figure. Then, $x_2$ , $y_2$ and 10 are a Pythagorean triple. From this, $x_2= 6$ or $x_2=8$ while $y_2= 6$ or $y_2=8$ . This leads us with the set of coordinates:

$(\pm 6, \pm 8)$ and $(\pm 8, \pm 6)$ . (A)

The next step is to find the coordinates of points that lie on lines which are perpendicular to the lines that joins the origin of the coordinate system with the set of points given in (A):

Let's do this for the point (6, 8).

The equation of the line that join the point (6, 8) with the origin (0, 0) has the equation $y = mx +n$ , however, we only need to find its slope in order to find a perpendicular line to it. Thus,

$m = \frac{y_2-y_1}{x_2-x_1} \\m = \frac{8-0}{6-0} \\m = 8/6$

Then, a perpendicular line has an slope $m_{\bot} = -\frac{1}{m} = -\frac{6}{8}$ (perpendicularity condition of two lines). With the equation of the slope of the perpendicular line and the given point (6, 8), together with the equation of the distance we can form a system of equations to find the coordinates of two points that lie on this perpendicular line.

$m_{\bot}=\frac{6}{8} = \frac{8-y}{6-x}\\ 6(6-x)+8(8-y)=0$ (1)

$d^2 = \sqrt{(y_o-y)^2+(x_o-x)^2} \\(10)^2=\sqrt{(8-y)^2+(6-x)^2}\\100 = \sqrt{(8-y)^2+(6-x)^2}$ (2)

This system has solutions in the coordinates (-2, 14) and (14, 2). Until here, we have three vertices of the square. Let's now find the fourth one in the same way we found the third one using the point (14,2). A line perpendicular to the line that joins the point (6, 8) and (14, 2) has an slope $m = 8/6$ based on the perpendicularity condition. Thus, we can form the system:

$\frac{8}{6} =\frac{2-y}{14-x} \\8(14-x) - 6(2-y) = 0$ (1)

$100 = \sqrt{(14-x)^2+(2-y)^2}$ (2)

with solution the coordinates (8, -6) and (20, 10). If you draw a line joining the coordinates (0, 0), (6, 8), (14, 2) and (8, -6) you will get one of the squares that fulfill the conditions of the problem. By repeating this process with the coordinates in (A), the following squares are found:

(0, 0), (6, 8), (14, 2), (8, -6)

(0, 0), (8, 6), (14, -2), (6, -8)
(0, 0), (-6, 8), (-14, 2), (-8, -6)
(0, 0), (-8, 6), (-14, -2), (-6, -8)

Now, notice that the equation of distance between the two points separated a distance of 10 has the trivial solution $(\pm10, 0)$ and $(0, \pm10)$ . By combining this points we get the following squares: