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tino4ka555 [31]
3 years ago
11

If 3x+5=14 what is x

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0

Answer:

3.666666666666667

Step-by-step explanation:

Akimi4 [234]3 years ago
3 0
X is 3 because 14- 5 = 9
And 3x3 =9 so 5+9=14
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1.25 is closer to 1.04 or not ?<br> plz heelp
anzhelika [568]

Answer:

NO

Step-by-step explanation:

I've already told you, it is closer to 1 than 1.25

3 0
2 years ago
How many times smaller is 2 x 10-13 than 4 x 10-10
polet [3.4K]

Answer:

30/7

Step-by-step explanation:

2 x 10 -13

20 - 13

7

4 x 10 -10

40 - 10

30

7 0
3 years ago
What is the approximate area of the unshaded region under the standard normal curve below? Use the portion of the standard norma
Harlamova29_29 [7]

The approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

It is given that the standard normal curve shows the shaded area in the curve.

It is required to find the approximate area of the unshaded region under the standard normal curve.

<h3>What is a normal distribution?</h3>

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

In the curve showing the shaded region area between:

\rm P(1 < Z < 2)

First, we calculate the shaded region area:

From the data given the value of Ф(1) = 0.8413.

P(Z<1)  = 0.8413  and

P(Z<2) =  0.9772

The area of the shaded region:

= P(Z<2) - P(Z<1)

=  0.9772 - 0.8413

= 0.1359

The area of the unshaded region:

= 1 - The area of the shaded region  ( because the curve is symmetric)

= 1 - 0.1359

= 0.8641 ≈ 0.86

Thus, the approximate area of the unshaded region under the standard normal curve is 0.86 the option third is correct.

Know more about the normal distribution here:

brainly.com/question/12421652

4 0
2 years ago
If men's heights are normally distributed with mean 68 and standard deviation 3.1 inches, and women's heights are normally distr
stira [4]

Answer:

the probability that the woman is taller than the man is  0.1423

Step-by-step explanation:

Given that :

the men's heights are normally distributed with mean \mu  68

standard deviation \sigma   = 3.1

And

the women's heights are normally distributed with mean \mu  65

standard deviation \sigma   = 2.8

We are to find the probability that the woman is taller than the man.

For woman now:

mean  \mu = 65

standard deviation \sigma = 2.8

P(x > 68 ) = 1 - p( x< 68)

\\ 1 -p  \ P[(x - \mu ) / \sigma < (68-25)/ 2.8]

= 1-P (z , 1.07)

Using z table,

= 1 - 0.8577

= 0.1423

Thus, the probability that the woman is taller than the man is  0.1423

6 0
3 years ago
Help i just need a quick answer thanks!
babunello [35]
1188
Hope this helps
7 0
3 years ago
Read 2 more answers
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