Ask question

Ask question

All categories

3 years ago

13

Malcolm buys 15 uniforms for the basketball team he pays 375 in total which ratios describe the relationship of price to uniform

s

1 answer:

Klio2033 [76]3 years ago

8 0

25:1 describes price to uniforms because each one costs $25

You might be interested in

What is the slope of the line given by the equation below?

andriy [413]

Answer:

D

Step-by-step explanation:

this would simplify, in slope-intercept form, as y= 15x - 66

7 0

2 years ago

PLSSSSSSSSSSSSSSSSSSSSSSSSSSS HELPPPPPPPPPPPPPPPPPPPPPPPPP

Nikitich [7]

Answer:

example...

2/3 = 4/6 has the same meaning as 2:3 = 4:6

Hope this helped!

7 0

2 years ago

Carissa bought a new pair of shoes that normally cost $50 for a sale price of $32.50 what was the percent of the discount

scoundrel [369]

The discount was 35%
to find that i did 32.5 / 50 and found 0.65 which means thats 32.5 is 65% of 50, but 17.5 was taken off and 17.5 is 35% of 50.

5 0

2 years ago

Madison and Tyler each wrote an expression that is equivalent to 14.1 (19.8 + 7.6). The expressions they created are shown in th

diamong [38]

Answer: Tyler used the distributive property.

Step-by-step explanation:

For the expression:

Madison wrote: which is by commutative property of addition.

The commutative property of addition says that , for a,b be any real number

Tyler wrote: which is by distributive propery.

The distributive property says that , for a,b,c be any real numbers.

Hence, the last option is correct.

6 0

3 years ago

Read 2 more answers

Solve the equation 2 sec² x = 3 - tan x for the domain 0° ≤ x ≤ 360°

vodka [1.7K]

$2 \sec^2 x = 3- \tan x \\\\\implies 2(1 +\tan^2 x) = 3- \tan x \\\\\implies 2 + 2 \tan^2 x +\tan x -3 =0\\\\\implies 2 \tan^2 x + \tan x -1 =0\\\\\implies 2u^2 + u -1 =0~~~ ;[\text{set} \tan x = u]\\\\\implies u = \dfrac{-1\pm \sqrt{1-4\cdot 2 \cdot (-1)}}{2(2)}\\\\\implies u =\dfrac{-1 \pm\sqrt{9}}{4}\\\\\implies u = \dfrac{-1 \pm 3}{4}\\\\\implies u = \dfrac{2}{4}=\dfrac 12~~ \text{or} ~~u =\dfrac{-4}{4} =-1\\\\$

$\implies \tan x = \dfrac 12 ~~ \text{or} ~~ \tan x =-1~~~ ;[\text{Substitute back u =tan x}]\\\\\text{Now,}~ \\\\\tan x = -1,\\\\\implies x = n\pi - \dfrac{\pi}4\\\\\\\text{For interval,}~ [0,2\pi) \\\\x = \dfrac{3\pi}4, \dfrac{7\pi}4\\\\\text{In degrees,}~ x = 135^{\circ}, x =315^{\circ}\\\\\tan x = \dfrac 12\\\\\implies x = n\pi + \tan^{-1} \left(\dfrac 12 \right)\\\\\text{For interval} ~[0,2\pi),\\\\$

$x=\tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\text{in degrees,} ~~x=\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\\\\text{Combine all solutions:}\\\\x=\dfrac{3\pi}4, \dfrac{7\pi}4, \tan^{-1} \left(\dfrac 12 \right), \left[\pi +\tan^{-1} \left( \dfrac 12 \right)\right]\\\\\\$

$\text{In degrees,}~ x = 135^{\circ},~315^{\circ},~\tan^{-1} \left(\dfrac 12 \right), \left[180^{\circ} +\tan^{-1} \left( \dfrac 12 \right)\right]$

4 0

1 year ago