Question

G(x)=4x+4 h(x)=x^2-x-2

Answer 1

Answer:

$\frac{g(x)}{h(x)} =\frac{4}{(x-2)}$

Step-by-step explanation:

$g(x)=4x+4\\h(x)=x^2-x-2$

First we can setup the equation as indicated

$\frac{g(x)}{h(x)} =\frac{4x+4}{x^2-x-2}$

In order to simplify this, we must factor both the numerator and denominator

$\frac{g(x)}{h(x)} =\frac{4(x+1)}{(x+1)(x-2)}$

The pair of (x+1)'s can cancel out and we are left with

$\frac{g(x)}{h(x)} =\frac{4}{(x-2)}$