The question is asking to convert the said decimal value in a simplest fraction form, base on my research and further calculation, I would say that the answer would be 3/10. I hope you are satisfied with my answer and feel free to ask for more

6 0

3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

2 years ago

If I add 9 to my number, I get 6. What is my number?

OverLord2011 [107]

negative 3...............................

3 0

3 years ago