Answer:
Here it is solved for rate:
log(1 + rate) = {log(total) -log(Principal)} ÷ Years
Let's work through your example:
log(1 + rate) = {log(6,680) -log(5,000)} / 6
log(1 + rate) = (3.8247764625 -3.6989700043) / 6
log(1 + rate) = 0.020967743
If we raise 10 to the 0.020967743 power
10^0.020967743 it produces 1 plus the rate
1 plus the rate = 10^0.020967743 = 1.0494644773
There fore the rate = .0494644773 which equals
4.94644773 per cent
Source: https://www.1728.org/compint2.htm
Step-by-step explanation:
Answer:T = 230.259 years
So choice B
Step-by-step explanation:
T = r / 100
T : 2 /100 = 0.02 per year
Now let’s solve for t using this equation
In ( A/P) / r
In ( 10000/100) / 0.02
Put this on calculator u get 230.259 years and now to the nearest year
is 230 years.
Hope this help
Answer:
The correct option is d i.e. scatter plot
Step-by-step explanation:
The correct option is d i.e. scatter plot
scatter plot will be the best option to display the variation of expenditure with respect to annual income.
on one axis annual income is used and on the other expenditure of the family. hence for a particular change in annual income, an impact on expenditure will easily be predicted.
0.8 = 8/10
simplified = 4/5 seconds
hope this helps
7n-13 is the answer for this