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goblinko [34]
3 years ago
14

Let f(x) = 5x - 2 and g(x) = x2.

Mathematics
2 answers:
Vlad [161]3 years ago
7 0

Answer:

5x3 - 2x2

Step-by-step explanation:

KIM [24]3 years ago
3 0
The answer will be B 
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I don't know how to do these
mixas84 [53]

Answer:

1. Below 2. B. d = 8h

Step-by-step explanation:

The graph is a bit confusing. But basically, substitute x for the numbers they give you.

5x

5 · 1 = 5 = y

5 · 2 = 10 = y

5 · 3 = 15 = y

5 · 4 = 20 = y

7x

7 · 1 = 7 = y

7 · 2 = 14 = y

7 · 3 = 21 = y

7 · 4 = 28 = y

4 0
3 years ago
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What is the answer of 9^2 • 9^3
zloy xaker [14]

Answer:

9^5

Step-by-step explanation:

the number you're multiplying stays the same and you add your powers I believe.

so it's basically 9•1 and the ^2+^3=^5

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3 years ago
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Solve for x in the equation x squared + 11 x + StartFraction 121 Over 4 EndFraction = StartFraction 125 Over 4 EndFraction.
Ira Lisetskai [31]

Answer:

Below

Step-by-step explanation:

● x^2 + 11x + 121/4 = 125/4

Substract 125/4 from both sides:

● x^2 + 11x + 121/4-125/4= 125/4 -125/4

● x^2 + 11x - (-4/4) = 0

● x^2 +11x -(-1) = 0

● x^2 + 11 x + 1 = 0

This is a quadratic equation so we will use the determinanant (b^2-4ac)

● a = 1

● b = 11

● c = 1

● b^2-4ac = 11^2-4*1*1 = 117

So this equation has two solutions:

● x = (-b -/+ √(b^2-4ac) ) / 2a

● x = (-11 -/+ √(117) ) / 2

● x = (-11 -/+ 3√(13))/ 2

● x = -0.91 or x = -10.9

Round to the nearest unit

● x = -1 or x = -11

The solutions are { -1,-11}

6 0
3 years ago
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State the following numbers correct to the decimal place given 78.333 (2d.p) 0.06045 (4d.p) 288.598 (2d.p) 0.1008 (3d.p)
Alex Ar [27]

78.33 (3 rounds down)

0.0605 (5 rounds up)

288.60 (8 rounds up, but there is a nine, so nine becomes 0 and 5 becomes 6)

0.101 (8 rounds up)

6 0
3 years ago
Find the area of a regular hexagon with a 48-inch perimeter.
kiruha [24]
A= \cfrac{3 \sqrt{3} }{2}*a^2 \ \ \ \ [a=sidelength]  \\   \\ a=48/6=8 \ in \\ \\ \\ A= \cfrac{3 \sqrt{3} }{2}*(8)^2=A= \cfrac{3 \sqrt{3} }{2}*64=3 \sqrt{3}*32= 96 \sqrt{3} \ \ in^2
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