56/90
" / " means divide
56 divided by 90 = 0.62 with a line over the 2 because it is repeating
(5, 12) e (-10, -3)
x.......y...1
5.....12..1
-10..-3..1
12x -10y -15 + 120 -5y + 3x = 0
12x + 3x - 10y - 5y - 15 + 120 = 0
15x - 15y + 105 = 0 :(5)
3x - 5y + 21 = 0
m = -a/b
m = -3/-5
m(5) = 3/5
y-yo = m(x-xo)
y-14 = 3/5*(x-7)
y-14 = 3x/5 - 7/5
3x/5 - y + 14 - 7/5 = 0
3x/5 - 5y/5 + 70/5 - 7/5 = 0
3x - 5y + 70 - 7 =0
3x - 5y + 63 = 0
m(s) = -3/-5 = 3/5
m(r) = m(s) --> são paralelas
You didn't give us enough informations to answer that?
Just divide your number and your % but don't put the %
Hope this helped!
first off, I'd like to point out that for the 5th test, he has 96, and that's +6 above 90, and therefore it should be 6.
if all the above/below numbers, summed up yield 0, that simply means the average is an even 90 on average for all 6 tests, if they yield above 0, is above on the average, and if it's below 0, a negative value, he needs to do more work.
-7+4-11+7+6-3 = -4.
you can think of it this way, if he had 90 on all 6 tests, the above/below row will show 0, 0, 0, 0, 0, 0. If any of the tests was above 90, that row will yield a sum more than 0, and if any of the tests were below, that sum will be a negative value.
