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givi [52]
2 years ago
8

Write 56/90 as a decimal.

Mathematics
2 answers:
BARSIC [14]2 years ago
8 0
56/90=0.622
this is a decimal number
gizmo_the_mogwai [7]2 years ago
5 0
56/90

" / " means divide

56 divided by 90 = 0.62 with a line over the 2 because it is repeating
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A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach
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Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that \mu = 130, \sigma = 30

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 130}{30}

X - 130 = 0.675*30

X = 150.25

A score of 150.25 is necessary to reach the 75th percentile.

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