Answer: 490 grams of the first alloy should be used.
30 grams of the second alloy should be used.
Step-by-step explanation:
Let x represent the weight of the first alloy in grams that should be used.
Let y represent the weight of the second alloy in grams that should be used.
A chemist has two alloys, one of which is 15% gold and 20% lead. This means that the amount of gold and lead in the first alloy is
0.15x and 0.2x
The second alloy contains 30% gold and 50% lead. This means that the amount of gold and lead in the second alloy is
0.3y and 0.5y
If the alloy to be made contains 82.5 g of gold, it means that
0.15x + 0.3y = 82.5 - - - - - - - - - - - -1
The second alloy would also contain 113 g of lead. This means that
0.2x + 0.5y = 113 - - - - - - - - - - - - -2
Multiplying equation 1 by 0.2 and equation 2 by 0.15, it becomes
0.03x + 0.06y = 16.5
0.03x + 0.075y = 16.95
Subtracting, it becomes
- 0.015y = - 0.45
y = - 0.45/- 0.015
y = 30
Substituting y = 30 into equation 1, it becomes
0.15x + 0.3 × 30 = 82.5
0.15x + 9 = 82.5
0.15x = 82.5 - 9 = 73.5
x = 73.5/0.15
x = 490
Answer:
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Step-by-step explanation:
did it on edge
Answer:
1+6y= "7y=7"
1+5y= "6y=4"
Step-by-step explanation:
X represents "1" so you replace your "X" with "1" and solve the equation.
Answer:
f(x)=x2,g(x)=f(3x)=(3x)2=9x2
Now to graph y=9x2. This is a parabola (U-shape), vertex at (0, 0), symmetric around y axis. When x=1/3 or -1/3, then y=1.
Hope this helps! :))
Answer:
(14,-4)(-4,-4)
Step-by-step explanation:
5+9=14
5-9=-4
