Question

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy?

Answer 1

There is an equal likely to pull out a strawberry candy and a pineapple candy because there is a 3 over 8 likely to pull out a pineapple candy.

Answer 2

Answer:

The probability of randomly pulling out a pineapple candy is fraction 3 over 8.

Step-by-step explanation:

A bowl contains only three flavors of candies: orange, strawberry and pineapple. Then, the sum of probabilities of pulling out any flavor of the candies need to be one, this can be write as:

$\frac{2}{8} +\frac{3}{8} + X = 1$

Where the fraction 2 over 8 is the probability of randomly pulling out an orange candy, the fraction 3 over 8 is the probability of randomly pulling out a strawberry candy and X is the probability of randomly pulling out a pineapple candy.

Solving for X, we get:

$X=1-\frac{2}{8} -\frac{3}{8}$

$X=\frac{3}{8}$

Finally, the probability of randomly pulling out a pineapple candy is fraction 3 over 8.